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Anit [1.1K]
3 years ago
6

When new understandings are achieved but the range of information able to be understood does not change, a learner’s zone of pro

ximal development __________.
A.
grows wider
B.
becomes bigger
C.
is smaller
D.
does not change


Please select the best answer from the choices provided

A
B
C
D
Physics
2 answers:
Nutka1998 [239]3 years ago
8 0

Answer:

the correct answer is C. is smaller

oksano4ka [1.4K]3 years ago
5 0
The development Is smaller
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At what speed, as a fraction of c, will a moving rod have a length 65% that of an identical rod at rest
dezoksy [38]

Answer:

v/c = 0.76

Explanation:

Formula for Length contraction is given by;

L = L_o(√(1 - (v²/c²))

Where;

L is the length of the object at a moving speed v

L_o is the length of the object at rest

v is the speed of the object

c is speed of light

Now, we are given; L = 65%L_o = 0.65L_o, since L_o is the length at rest.

Thus;

0.65L_o = L_o[√(1 - (v²/c²))]

Dividing both sides by L_o gives;

0.65 = √(1 - (v²/c²))

Squaring both sides, we have;

0.65² = (1 - (v²/c²))

v²/c² = 1 - 0.65²

v²/c² = 0.5775

Taking square root of both sides gives;

v/c = 0.76

6 0
3 years ago
Water drops from the nozzle of a shower onto the floor 81 inches below. The drops fall at regular intervals of time, the first d
Alexxx [7]

Answer:

0.91437 m

0.22859 m

Explanation:

g = Acceleration due to gravity = 9.81 m/s² = a

s=81\ inches=81\times 0.0254=2.0574\ m

s=ut+\frac{1}{2}at^2\\\Rightarrow 2.0574=0t+\frac{1}{2}\times 9.81\times t^2\\\Rightarrow t=\sqrt{\frac{2.0574\times 2}{9.81}}\\\Rightarrow t=0.64764\ s

When the time intervals are equal, if four drops are falling then we have 3 time intervals.

So, the time interval is

t'=\dfrac{t}{3}\\\Rightarrow t'=\dfrac{0.64764}{3}\\\Rightarrow t'=0.21588\ s

For second drop time is given by

t''=2t'\\\Rightarrow t''=2\times 0.21588\\\Rightarrow t''=0.43176\ s

Distance from second drop

s=ut+\dfrac{1}{2}at^2\\\Rightarrow y''=ut''+\dfrac{1}{2}at''^2\\\Rightarrow s=0\times t+\dfrac{1}{2}\times 9.81\times 0.43176^2\\\Rightarrow s=0.91437\ m

Distance from second drop is 0.91437 m

Distance from third drop

s=ut+\dfrac{1}{2}at^2\\\Rightarrow y''=ut'+\dfrac{1}{2}at'^2\\\Rightarrow s=0\times t+\dfrac{1}{2}\times 9.81\times 0.21588^2\\\Rightarrow s=0.22859\ m

Distance from third drop is 0.22859 m

6 0
3 years ago
A sock stuck to the inside of the clothes dryer spins around the drum once every 2.0 s at a distance of 0.50 m from the center o
Rashid [163]

a) 1.57 m/s

The sock spins once every 2.0 seconds, so its period is

T = 2.0 s

Therefore, the angular velocity of the sock is

\omega=\frac{2\pi}{T}=\frac{2\pi}{2.0}=3.14 rad/s

The linear speed of the sock is given by

v=\omega r

where

\omega is the angular velocity

r = 0.50 m is the radius of the circular path of the sock

Substituting, we find:

v=(3.14)(0.50)=1.57 m/s

B) Faster

In this case, the drum is twice as wide, so the new radius of the circular path of the sock is twice the previous one:

r' = 2r = 1.00 m

At the same time, the drum spins at the same frequency as before, therefore the angular frequency as not changed:

\omega' = \omega = 3.14 rad/s

Therefore, the new linear speed would be:

v'=\omega' r' = \omega (2r)

And substituting,

v'=(3.14)(1.00)=3.14 rad/s = 2v

So, we see that the linear speed has doubled.

8 0
3 years ago
Se coloca una tuerca con una llave, como muestra la figura, si el brazo r= 30 cm y el torque de apriete recomendado para la fuer
irina [24]

Answer:

F = 100 N

Explanation:

The torque is given by the expression

      τ = F x r

where bold letters indicate vectors, the magnitude of this expression is

     τ = F r sin θ

In general, when tightening a nut, the force is applied perpendicular to the arm, therefore  θ = 90 and sin 90 = 1

      τ = F r

      F = τ / r

calculate

      F = 30 / 0.30

      F = 100 N

6 0
3 years ago
Calculate the mass of air of density 1.2kgm-3 in a room of dimensions 8m by 6m by 4m.
77julia77 [94]

Answer:

230.4kg

Explanation:

volume of the room = l× b×h

volume= 8×6×4

volume=192m3

density= mass/volume

hence mass= density × volume

mass= 1.2kgm-3 × 192m3

mass= 230.4kg

5 0
2 years ago
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