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3 years ago

A rocket has a mass 280(103) slugs on earth. Specify its mass in SI units, and its weight in SI units.

1 answer:

8 0

To solve this problem we will apply the concepts related to the conversion of units for which we will have that 1 slug is equal to 14.59kg. At the same time we will use Newton's second law for which weight is defined as the product between mass and acceleration (Due to gravity). This is then

A: Using the conversion ratio of slug to kilogram we have to,

$1 slug = 14.59kg$

Then

$m = 280*10^3 slugs (\frac{14.59kg}{1slug})$

$m = 4.09*10^6kg$

B: Using Newton's second law we have to,

$W = mg$

$W = (4.09*10^6)(9.8)$

$W = 40034960N\approx 4*10^7N$

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Which is usually greater for a pair of surfaces, the coefficient of static friction or the coefficient of sliding friction? why

lorasvet [3.4K]

Explanation :

Static friction is the frictional force between two objects that are at rest. While sliding friction is the frictional force between two objects in contact and are sliding w.r.t each other.

Static friction is usually greater than sliding friction because in static friction the contact forces is more and the interlocking between objects is tight as compared to sliding friction.

5 0

3 years ago

A. How long (in ns) does it take light to travel 1.0 m in a vacuum?

suter [353]

Answer:

a) 3.33 ns

b) Water distance = 0.75 m

Glass distance = 0.66 m

Diamond distance = 0.41 m

Explanation:

We take the speed of light, c = m/s.

Speed = distance/time

Time = distance/speed

$t=\dfrac{1}{3.0\times10^{8}}=3.33\times10^{-9}$

t = 3.33 ns

Refractive index, n = speed of light in vacuum / speed of light in medium

$n=\dfrac{c}{s}$

$s=\dfrac{c}{n}$

$d=s\times t$

$d=\dfrac{c}{n}\times \dfrac{1}{c}$

$d=\dfrac{1}{n}$

Thus, the distance traveled in the same time is numerically equal to the reciprocal of the refractive index.

For water n = 1.333

d = 1/1.333 = 0.75 m

For glass n = 1.517

d = 0.66 m

For diamond n = 2.417

d = 0.41 m

4 0

3 years ago

What is the electric potential at a point between the 2.5-ω and 5.5-ω resistors, if the electric potential at the positive termi

algol13

If the +12V is on one side of the 2.5 ohm R then.............

V = (2.5/8) x 12 otherwise......

V = (5.5/8) x 12

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2 years ago

A runner moves 2.88 m/s north. She accelerates at 0.350 m/s^2 at a -52.0 angle. At the point in the motion where she is running

MrRissso [65]

The runner has initial velocity vector

$\vec v_0=\left(2.88\dfrac{\rm m}{\rm s}\right)\,\vec\jmath$

and acceleration vector

$\vec a=\left(0.350\dfrac{\rm m}{\mathrm s^2}\right)(\cos(-52.0^\circ)\,\vec\imath+\sin(-52.0^\circ)\,\vec\jmath)$

so that her velocity at time $t$ is

$\vec v=\vec v_0+\vec at$

She runs directly east when the vertical component of $\vec v$ is 0:

$2.88\dfrac{\rm m}{\rm s}+\left(0.350\,\dfrac{\rm m}{\mathrm s^2}\right)\sin(-52.0^\circ)\,t=0\implies t=10.4\,\rm s$

It's not clear what you're supposed to find at this particular time... possibly her position vector? In that case, assuming she starts at the origin, her position at time $t$ would be

$\vec x=\vec v_0t+\dfrac12\vec at^2$