Se coloca una tuerca con una llave, como muestra la figura, si el brazo r= 30 cm y el torque de apriete recomendado para la fuer
za es de 30 Nxm, Cuàl debe ser el valor de la fuerza F aplicada?
1 answer:
Answer:
F = 100 N
Explanation:
The torque is given by the expression
τ = F x r
where bold letters indicate vectors, the magnitude of this expression is
τ = F r sin θ
In general, when tightening a nut, the force is applied perpendicular to the arm, therefore θ = 90 and sin 90 = 1
τ = F r
F = τ / r
calculate
F = 30 / 0.30
F = 100 N
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