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Furkat [3]
3 years ago
13

Se coloca una tuerca con una llave, como muestra la figura, si el brazo r= 30 cm y el torque de apriete recomendado para la fuer

za es de 30 Nxm, Cuàl debe ser el valor de la fuerza F aplicada?
Physics
1 answer:
irina [24]3 years ago
6 0

Answer:

F = 100 N

Explanation:

The torque is given by the expression

      τ = F x r

where bold letters indicate vectors, the magnitude of this expression is

     τ = F r sin θ

In general, when tightening a nut, the force is applied perpendicular to the arm, therefore  θ = 90 and sin 90 = 1

      τ = F r

      F = τ / r

calculate

      F = 30 / 0.30

      F = 100 N

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Describe three societal needs that drive scientific endeavor and give an example of a scientific endeavor associated with each.
Trava [24]

The answer is:


1. Cure disease

2. Improve livelihoods

3. Understand nature and themselves.


1. Disease has plagued humans since the first man. Therefore, man has always used science to seek a cure for any emerging disease such as cancer today

2. Humans use science to improve livelihoods such as means of faster traveling and increasing yields in the fields

3. Science has been used to understand humans and the environment in which they live. This is evident with the numerous scientific probes that explore the earth and space collecting and analyzing data.


6 0
4 years ago
A spring has a natural length of 0.5 m and was stretched by 0.02 m. if the spring had a resultant energy of 0.5 j what is the sp
Anna71 [15]

\textbf{2500 }\dfrac{\textbf{kg}}{\textbf{s}^{\textbf{2}}}

Explanation:

       Natural length of a spring is 0.5\text{ }m. The spring is streched by 0.02\text{ }m. The resultant energy of the spring is 0.5\text{ }J.

       The potential energy of an ideal spring with spring constant k and elongation x is given by \dfrac{1}{2}kx^{2}.

       So, in the current problem, the natural length of the spring is not required to find the spring constant k.

       \text{Potential Energy in the spring = }\dfrac{1}{2}kx^{2}\\0.5\text{ }J\text{ }=\text{ }\dfrac{1}{2}k(0.02\text{ }m)^{2}\\k\times0.0004\text{ }m^{2}\text{ }=\text{ }1\text{ }J\text{ }=\text{ }1\text{ }kg\frac{m^{2}}{s^{2}}\\k\text{ }=\text{ }\dfrac{1\text{ }kg\dfrac{m^{2}}{s^{2}}}{0.0004\text{ }m^{2}}\text{ }=\text{ }2500\text{ }\frac{kg}{s^{2}}

∴ The spring constant of the spring = 2500\text{ }\frac{kg}{s^{2}}

4 0
3 years ago
Last night Mookie Betts hit a baseball at 32.5 m/s at a 45° angle. Betts
podryga [215]

Answer:

a) Since the height of the baseball at 99 m was 8.93 m and the fence at that distance is 3m tall, the hit was a home run.

b) The total distance traveled by the baseball was 108.7 m.

Explanation:

a) To know if the hit was a home run we need to calculate the height of the ball at 99 m:

y_{f} = y_{0} + v_{0_{y}}t - \frac{1}{2}gt^{2}

Where:

y_{f}: is the final height =?

y_{0}: is the initial height = 1 m

v_{0_{y}: is the initial vertical velocity = v₀sin(45)

v₀: is the initial velocity = 32.5 m/s

g: is the gravity = 9.81 m/s²

t: is the time    

First, we need to find the time by using the following equation:

t = \frac{x}{v_{0_{x}}} = \frac{99 m}{32.5 m/s*cos(45)} = 4.31 s

Now, the height is:

y_{f} = y_{0} + v_{0_{y}}t - \frac{1}{2}gt^{2} = 1m + 32.5 m/s*sin(45)*4.31 s - \frac{1}{2}9.81 m/s^{2}*(4.31 s)^{2} = 8.93 m      

Since the height of the baseball at 99 m was 8.93 m and the fence at that distance is 3m tall, the hit was a home run.

b) To find the distance traveled by the baseball first we need to find the time of flight:

y_{f} = y_{0} + v_{0_{y}}t - \frac{1}{2}gt^{2}

0 = 1 m + 32.5m/s*sin(45)t - \frac{1}{2}9.81 m/s^{2}t^{2}

1 m + 32.5m/s*sin(45)t - \frac{1}{2}9.81 m/s^{2}t^{2} = 0

By solving the above quadratic equation we have:

t = 4.73 s

Finally, with that time we can find the distance traveled by the baseball:

x = v_{0_{x}}*t = 32.5 m/s*cos(45)*4.73 s = 108.7 m

Hence, the total distance traveled by the baseball was 108.7 m.

I hope it helps you!                                                                                  

4 0
3 years ago
In an isolated system, Bicycle 1 and Bicycle 2, each with a mass of 10 kg,
dimulka [17.4K]

Answer: 20 kgm/s

Explanation:

Given that M1 = M2 = 10kg

V1 = 5 m/s , V2 = 3 m/s

Since momentum is a vector quantity, the direction of the two object will be taken into consideration.

The magnitude of their combined

momentum before the crash will be:

M1V1 - M2V2

Substitute all the parameters into the formula

10 × 5 - 10 × 3

50 - 30

20 kgm/s

Therefore, the magnitude of their combined momentum before the crash will be 20 kgm/s

7 0
3 years ago
How do surface currents affect climate
Bumek [7]
Ocean currents<span> act much like a conveyer belt, transporting warm water and precipitation from the equator toward the poles and cold water from the poles back to the tropics. Therefore, </span>currents<span> regulate global </span>climate<span>, helping to counteract the uneven distribution of solar radiation reaching Earth's </span>surface<span>.</span>
8 0
4 years ago
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