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nasty-shy [4]
3 years ago
6

Write the balanced COMPLETE ionic equation for the reaction when

Chemistry
1 answer:
Vera_Pavlovna [14]3 years ago
3 0

Answer:

Ba²⁺(aq) + 2 NO₃⁻(aq) + 2 Rb⁺(aq) + 2 OH⁻(aq) = Ba(OH)₂(s) + 2 Rb⁺(aq) + 2NO₃⁻(aq)

Explanation:

Let's consider the molecular equation between barium nitrate and rubidium hydroxide to produce barium hydroxide and rubidium nitrate.

Ba(NO₃)₂(aq) + 2 RbOH(aq) = Ba(OH)₂(s) + 2 RbNO₃(aq)

The complete ionic equation includes all the ions and the molecular species.

Ba²⁺(aq) + 2 NO₃⁻(aq) + 2 Rb⁺(aq) + 2 OH⁻(aq) = Ba(OH)₂(s) + 2 Rb⁺(aq) + 2NO₃⁻(aq)

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A temprature change in a reaction indicates
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Chemical change

Explanation:

Often times, in chemical reactions, a temperature change indicates that a chemical change has occurred.

What is a chemical change?

  • It is a kind of change in which new products are formed.
  • Chemical changes are usually accompanied by energy changes in reactions.
  • The process is not easily reversible.
  • It usually involve a change in mass.
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When temperature change occurs, it usually denotes chemical change.

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3 0
3 years ago
Jason has five equally massed lead fishing weights, each weighing 250 grams. What is the total mass of the five leaf fishing wei
shusha [124]

Answer:

Total mass of 5 lead fishing weights= 1250 grams

Explanation:

Given:

Mass of a lead fishing weight =250 grams

To find total mass of 5 such fishing weights

We can apply unitary method to find total mass of 5 fishing weights.

If mass of 1 lead fishing weight = 250 grams

∴ Total mass of 5 lead fishing weights = 250\times 5 =1250\ grams

5 0
3 years ago
Answer These PLEASE!!!11
Anit [1.1K]

Electrical than Chemical

6 0
3 years ago
The ____________________ metals are all of the elements located in groups 3-12 on the Periodic Table.
S_A_V [24]

Answer:

Transition Metals are all of the elements kn group 3-12.

6 0
4 years ago
How many molecules of XeF6 are formed from 12.9 L of F2 (at 298 K and 2.6 atm) according to 11) the following reaction? Assume t
ddd [48]

Answer:

#Molecules XeF₆ = 2.75 x 10²³ molecules XeF₆.

Explanation:

Given … Excess Xe + 12.9L F₂ @298K & 2.6Atm => ? molecules XeF₆

1. Convert 12.9L 298K & 2.6Atm to STP conditions so 22.4L/mole can be used to determine moles of F₂ used.

=> V(F₂ @ STP) = 12.6L(273K/298K)(2.6Atm/1.0Atm) = 30.7L F₂ @ STP

2. Calculate moles of F₂ used

=> moles F₂ = 30.7L/22.4L/mole = 1.372 mole F₂ used

3. Calculate moles of XeF₆ produced from reaction ratios …

Xe + 3F₂ => XeF₆ => moles of XeF₆ = ⅓(moles F₂) = ⅓(1.372) moles XeF₆ = 0.4572 mole XeF₆

4. Calculate number molecules XeF₆ by multiplying by Avogadro’s Number  (6.02 x 10²³ molecules/mole)

=> #Molecules XeF₆ = 0.4572mole(6.02 x 10²³ molecules/mole)

                                  = 2.75 x 10²³ molecules XeF₆.

8 0
3 years ago
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