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k0ka [10]
3 years ago
5

The first periodic table were arranged elements in order of

Chemistry
1 answer:
FrozenT [24]3 years ago
3 0

Answer:

in order of atomic mass

Explanation:

apex

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HELP ASAP !!!!!!Can someone tell me easy one line definitions of atomic number, mass number, and isotopes
rusak2 [61]

Answer:

Fundamental properties of atoms including atomic number and atomic mass. The atomic number is the number of protons in an atom, and isotopes have the same atomic number but differ in the number of neutrons.

Explanation:

Fundamental properties of atoms including atomic number and atomic mass. The atomic number is the number of protons in an atom, and isotopes have the same atomic number but differ in the number of neutrons.

5 0
2 years ago
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ArbitrLikvidat [17]

Answer:

<h3>Exothermic Process</h3>

Explanation:

7 0
3 years ago
Calculate the volume of an object with dimensions measuring: 15cm x 6cm x 10cm
Oksanka [162]

Answer:

15 X 6 X 10 = 900 cm³

Explanation:

4 0
2 years ago
When magnesium reacts with hydrochloric acid, hydrogen gas is formed: 2HCl + Mg → H2 + MgCl2. What is the volume of hydrogen pro
Maksim231197 [3]

Answer:- C. 16.4 L

Solution:- The given balanced equation is:

2HCl+Mg\rightarrow H_2+MgCl_2

From this equation, there is 2:1 mol ratio between HCl and hydrogen gas. First of all we calculate the moles of hydrogen gas from given grams of HCl using stoichiometry and then the volume of hydrogen gas could be calculated using ideal gas law equation, PV = nRT.

Molar mass of HCl = 1.008 + 35.45 = 36.458 gram per mol

The calculations are shown below:

49.0gHCl(\frac{1molHCl}{36.458gHCl})(\frac{1molH_2}{2molHCl})

= 0.672molH_2

Now we will use ideal gas equation to calculate the volume.

n = 0.672 mol

T = 25 + 273 = 298 K

P = 101.3 kPa = 1 atm

R = 0.0821\frac{atm.L}{mol.K}

PV = nRT

1(V) = (0.672)(0.0821)(298)

V = 16.4 L

From calculations, 16.4 L of hydrogen gas are formed and so the correct choice is C.

7 0
3 years ago
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Elena-2011 [213]

Answer:

a

Explanation:

8 0
3 years ago
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