1) in periodic acid (HIO₄), iodine has oxidation number +7, hydrogen has oxidation number +1, oxygen has -2, compound has neutral charge:
+1 + x + 4 · (-2) = 0.
x = +7.
2) in molecule of iodine (I₂), iodine has oxidation number 0, because iodine is nonpolar molecule.
3) in sodium iodide (NaI), iodine has oxidation number -1, sodium has oxidation number +1:
+1 + x = 0.
x = -1.
4) in iodic acid (HIO₃), iodine has oxidation number +5, hydrogen has oxidation number +1, oxygen has -2, compound has neutral charge:
+1 + x + 3 · (-2) = 0.
x = +5.
Answer:
The hydrolysis in aqueous HCl of compound A can lead to the formation of a carboxylic acid and an alcohol.
Explanation:
The picture shows the structures of compound A, benzoncaine and the possible products of the proposed reaction.
The acidic hydrolysis is the inverse of the esterification reaction. Therefore, the ester group of compund A will react to form the equivalent carboxylic acid and alcohol.
In order to form benzocaine, the hydrolysis happens in with the nitrile group.
is 7 cus the valance electron for sodium is Ne 3s1 and for chlorine is Ne 3s13p5
Answer molecule
Explanation: The combination of two or more atoms, from the same or different elements, creates a molecule. Compounds are a type of molecules made of atoms from different elements held together by chemical bonds.
