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Pani-rosa [81]
3 years ago
5

Can someone help me on this

Chemistry
1 answer:
xz_007 [3.2K]3 years ago
8 0
155,500



I did this to the best of my ability. I have a hard time comprehending things sometimes so I’m so so so sorry if it’s wrong
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If 11g of a gas occupies 5.6dm'3at s.t.p., calculate it's vapour density (1.0mol of a gas occupies 22.4dm'3at s.t.p.).​
11111nata11111 [884]

Answer:

{ \boxed{ \bf{vapour \: density = 2 \times molecular \: mass}}} \\{ \tt{ PV= (\frac{m}{ m_{r}}) RT}} \\ { \tt{3 \times 5.6 =  \frac{11}{m _{r}}  \times 0.0831 \times 273}} \\ { \tt{m _{r} = 14.85 \: g}} \\  \\ { \bf{vapour \: density = 2 \times m _{r}}} \\  = 2 \times 14.85 \\  = 29.7 \: { \tt{g {dm}^{ - 3} }}

7 0
3 years ago
Why do you think the atomic number is basically represented by the number of protons and not the number of electrons?
Naya [18.7K]

Answer:

The atomic number equals the charge on the nucleus. It therefore also equals the number of protons in the nucleus and also equals numerically the number of electrons in the neutral atom. i think so, hope this helps you

Explanation:

6 0
3 years ago
A chemist prepares a solution of silver(I) nitrate by measuring out of silver(I) nitrate into a volumetric flask and filling the
leva [86]

Answer:

3.33 M

Explanation:

It seems your question is incomplete, however, that same fragment has been found somewhere else in the web:

" <em>A chemist prepares a solution of silver nitrate (AgNO3) by measuring out 85.g of silver nitrate into a 150.mL volumetric flask and filling the flask to the mark with water.</em>

<em>Calculate the concentration in mol/L of the chemist's silver nitrate solution. Be sure your answer has the correct number of significant digits.</em> "

In this case, first we <u>calculate the moles of AgNO₃</u>, using its molecular weight:

  • 85.0 g AgNO₃ ÷ 169.87 g/mol = 0.500 mol AgNO₃

Then we<u> convert the 150 mL of the volumetric flask into L</u>:

  • 150 / 1000 = 0.150 L

Finally we <u>divide the moles by the volume</u>:

  • 0.500 mol AgNO₃ / 0.150 L = 3.33 M
4 0
3 years ago
I don’t understand how to do this
djverab [1.8K]
Carbon dioxide is a carbon atom and two oxygen atoms, therefore CO2

For the others, they are hydrocarbons.
The first part of the name is determined by how many carbon atoms there are. The second part, is by the type. Alcohol, Alkane, Alkene, alkynes, acid, esters, amides.

7 0
4 years ago
At a pressure of 782.3 mm Hg and 34.4 °C, a certain gas has a volume of 362.4 mL. What will
german

Answer: v2=331.289mL

Explanation:

Formula for ideal gas law is p1v1/T1=p2v2/T2

P1=782.3mmHg

P2=769mmHg at STP

V1=362.4mL

V2=?

T1=273+34.4=307.4k

T2=273k at STP

Then apply the formula and make v2 the subject of formula

V2= 782.3×362.4×273/760×307.4

V2=77397006.96/233624

V2=331.289mL

7 0
3 years ago
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