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3 years ago

14

A fisherman noticed that a wave strikes the boat side every 5 seconds. The distance between two consecutive crest is 1.5m. What

is the period frequency of the wave?

1 answer:

GrogVix [38]3 years ago

8 0

5/1.5=7 I think that is the answer

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An arrow, starting from rest, leaves the bow with a speed of25

xz_007 [3.2K]

Answer:

The speed will be $v_f= 43.30 \frac{m}{s}$

Explanation:

We can use the following kinematics equation

$v_f^2-v_i^2=2 \ a \ d$

where $v_f$ is the final speed, $v_i$ its the initial speed, a is the acceleration, and d the distance.

The force will be tripled, the force is:

$\vec{F} = m \vec{a}$

in 1D

$F = m a$

Now, for the original problem, we have

$(25 \frac{m}{s})^2-(0 \frac{m}{s})^2=2 \ a' \ d'$

$(25 \frac{m}{s}))^2=2 \ a' \ d'$

$625 \frac{m^2}{s^2}=2 \ a' \ d'$

For the second problem, we have

$(v_f})^2-(v_i)^2=2 \ a'' \ d''$

starting from the rest, we have the same initial velocity.

$(v_f})^2-(0\frac{m}{s})^2=2 \ a'' \ d''$

$(v_f})^2=2 \ a'' \ d''$

As the force is tripled, we have:

$F'' = 3 F'$

$m'' \ a'' = 3 m' \ a'$

But the mass its the same, so

$m' \ a'' = 3 m' \ a'$

$a'' = 3 \ a'$

So the acceleration its also tripled.

$(v_f})^2=2 \ (3 * a') \ d''$

$(v_f})^2=3 ( 2 \ ( a' \ d'' )$

As the distance traveled by the arrow must also be the same, we have:

$(v_f})^2=3 ( 2 \ ( a' \ d' )$

$(v_f})^2=3 (625 \frac{m^2}{s^2})$

$v_f= \ sqrt{3 (625 \frac{m^2}{s^2})}$

$v_f= \ sqrt{3} 25 \frac{m}{s}$

$v_f= 43.30 \frac{m}{s}$

And this will be the speed from the arrow leaving the bow.

5 0

4 years ago

A 2.0 kilogram mass is located 3.0 meters above the surface of earth. what is the magnitude of earth's gravitational field stren

MissTica

Why do you think its important for givernment offcials to take an oath of ofice?

7 0

3 years ago

2) A ray of light in air is approaching the boundary with water at an

KiRa [710]

Answer:

Explanation:

ASSUMING the 52° is the angle of incidence measured from the perpendicular to the surface

n₁sinθ₁ = n₂sinθ₂

1 sin52 = 1.33sinθ₂

θ₂ = arcsin(sin52 / 1.33)

θ₂ = 36°

as measured from the perpendicular to the surface

5 0

3 years ago

What is the process called in which water vapor and carbon dioxide retain heat?

saw5 [17]

The process in which water vapour and carbon dioxide traps heat is called the “greenhouse effect”.

The greenhouse effect is a natural phenomenon which occurs every day. To illustrate an example of this natural phenomenon, d<span>uring the day the Sun shines through the atmosphere. Earth's surface warms up because of the sunlight. Meanwhile at night in the absence of the sunlight, Earth's surface cools back and releasing the heat back into the air. However some of the heat is retained by the greenhouse gases (such as carbon dioxide and water vapour) in the atmosphere. This process what keeps our planet Earth warm and cozy at an average temperature of 16°C.</span>

<span>
</span>

<span>Answer:</span>

<span>greenhouse effect</span>

6 0

3 years ago

Identrying the speed of the Cart

aleksklad [387]

The speed of the cart after 3 seconds of Low fan speed is equal to 54 cm/s.

<h3>How to calculate the speed?</h3>

Mathematically, speed can be calculated by using this formula;

Speed = distance/time

At Low fan speed after 3 seconds, the distance covered is 162 cm:

Speed = 162/3

Speed = 54 cm/s.

At Medium fan speed after 5 seconds, the distance covered is 600 cm:

Speed = 600/5

Speed = 120 cm/s.

At High fan speed after 2 seconds, the distance covered is 128 cm:

Speed = 128/2

Speed = 64 cm/s.

Read more on speed here: brainly.com/question/17350470

#SPJ1

6 0

2 years ago

Read 2 more answers