<span>553 ohms
The Capacitive reactance of a capacitor is dependent upon the frequency. The lower the frequency, the higher the reactance, the higher the frequency, the lower the reactance. The equation is
Xc = 1/(2*pi*f*C)
where
Xc = Reactance in ohms
pi = 3.1415926535.....
f = frequency in hertz.
C = capacitance in farads.
I'm assuming that the voltage and resistor mentioned in the question are for later parts that are not mentioned in this question. Reason is that they have no effect on the reactance, but would have an effect if a question about current draw is made in a later part. With that said, let's calculate the reactance.
The 120 rad/s frequency is better known as 60 Hz.
Substitute known values into the formula.
Xc = 1/(2*pi* 60 * 0.00000480)
Xc = 1/0.001809557
Xc = 552.6213302
Rounding to 3 significant figures gives 553 ohms.</span>
Answer: then you’re not sick d u h
Explanation:
Answer:
w = √ 1 / CL
This does not violate energy conservation because the voltage of the power source is equal to the voltage drop in the resistence
Explanation:
This problem refers to electrical circuits, the circuits where this phenomenon occurs are series RLC circuits, where the resistor, the capacitor and the inductance are placed in series.
In these circuits the impedance is
X = √ (R² + (
-
)² )
where Xc and XL is the capacitive and inductive impedance, respectively
X_{C} = 1 / wC
X_{L} = wL
From this expression we can see that for the resonance frequency
X_{C} = X_{L}
the impedance of the circuit is minimal, therefore the current and voltage are maximum and an increase in signal intensity is observed.
This does not violate energy conservation because the voltage of the power source is equal to the voltage drop in the resistence
V = IR
Since the contribution of the two other components is canceled, this occurs for
X_{C} = X_{L}
1 / wC = w L
w = √ 1 / CL
<h2>
Answer:</h2><h3><u>QUESTION①)</u></h3>
<em>✔ First step : calculate the kinetic energy that this car requires to reach 95 km/h</em>
95/ 3,6 ≈ 26,4 m/s
<em>Ec = ½ m x V² </em>
With Ec in J; m in kg; and V in m/s
- Ec = ½ 1750 x 26,4²
- Ec ≈ 610 000 J
<em>✔ Knowing that the car has a p power of 215,000 W, so :
</em>
T = E/P
- T = 610 000/215 000
- T ≈ 2.8 s
<h3>
The car takes 2.8 s to reach 95 km/h </h3>
<h3><u>QUESTION②)</u></h3>
N = 2,8/6,5 x 100 = 43.07
<h3>The car efficiency is 43 % </h3>
(1) Answer:
6 Newtons
Explanation:
The net force is (mass) x (acceleration) = (3 kg) x (2.0 m/s^2) = 6 N
(2) Answer:
-98 Newtons
Explanation:
Weight (force due to gravity) is (mass) x (gravitational acceleration) = (10 kg) x (- 9.8 m/s^2) = -98 N
The negative sign due to negative acceleration indicates the gravitational force pointing in the negative direction within the defined coordinate system.