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jarptica [38.1K]
3 years ago
7

a car moving at 30.0 m/s slows uniformly to a speed of 10.0 m/s in a time of 5.00 s determine the. acceleration of the car

Physics
1 answer:
netineya [11]3 years ago
7 0

Answer: -4m/s^{2}

Explanation:

Acceleration a is defined as the variation of Velocity \Delta V in time \Delta t :  

a=\frac{\Delta V}{\Delta t}

In this case \Delta V=10m/s - 30m/s  and \Delta t=5 s.

Therefore:

a=\frac{10m/s - 30m/s}{5 s}

a=\frac{-20m/s}{5 s}

a=-4 m/s^{2}  Note the negative sign indicates the car is slowing

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Which best explains why water boils in a pot sitting over fire?
gregori [183]
The Thermal energy from the fire moves to the water in the forms of heat.

Thermal energy is the energy that comes from heat which generated by the movements of tiny particles of an obejct. The faster the particles move, the more heat energy it will generates

Hope this help you out
7 0
3 years ago
Read 2 more answers
How many Joules of energy are required to run a 100W light bulb for one day?
Vlada [557]

The following are the answers to the questions presented:

a. The joules of energy required to run a 100W light bulb for one day is 8640000J
b. The amount of coals that has to be burned to light that light bulb for one day is 0.96kg

The solution would be like this for this specific problem:

<span>P=<span>W/s</span>→W=Pt=100W1day <span><span>24h/</span><span>1day </span></span><span><span>3600s/</span><span>1h</span></span>=8640000J</span>

<span>W=<span>30/100</span>wm→m=<span><span>100W/</span><span>30w</span></span>=<span><span>100×8640000J/</span><span>30×30×<span>10in thepowerof6 </span><span>J/<span>kg</span></span></span></span>=0.96kg</span>

<span>I am hoping that these answers have satisfied your queries and it will be able to help you in your endeavors, and if you would like, feel free to ask another question.</span>

4 0
3 years ago
When air mass is caught between two cold fronts the result is a _______ front.
Gre4nikov [31]
A. Occluded
Explanation- At an occluded front, the cold air mass from the cold front meets the cool air that was ahead of the warm front.
3 0
3 years ago
A 64 kg swimmer jumps, with a velocity of 4.2 m/s, off the front of a 25 kg kayak when the kayak is moving forward at a velocity
Crank

Answer:

3.88m/s

Explanation:

Using the law of conservation of momentum

m1u1+m2u2 = (m1+m2)v

m1 and m2 are the masses

u1 and 2 are the initial velocities

v is the final velocity

Given

m1 = 64kg

u1 = 4.2m/s

m2 = 25kg

u2 = 3.2m/s

Required

Final velocity v

Substitute the given values into the formula

64(4.2)+25(3.2) = (65+25)v

268.8+80 = 90v

348.8 = 90v

v = 348.8/90

v = 3.88m/s

Hence the velocity of the kayak after the swimmer jumps off is 3.88m/s

8 0
3 years ago
A brass washer has an outside diameter of 4.50 cm with a hole of diameter 1.25 cm and is 1.50 mm thick. The density of brass is
-Dominant- [34]
We will find the mass from 
mass = density x volume 
We are told the density and must find the volume from the dimensions given 
the volume of the washer will be the area x thickness (remembering to convert all measurements to meters) 
if the washer had no hole, its area would be pi (0.0225m)^2 (remember to convert to meters and to use radius) 
the area of the hole is pi(0.00625m)^2 
so the area of the washer is pi[(0.0225m)^2 - (0.00625m)^2] = 1.5x10^-3 m 
the volume of the washer is 1.5x10^-3 m x 1.5x10^-3 m = 2.25x10^-6 m^3 (the thickness of the washer is 1.5 mm = 1.5x10^-3m) 
thus, the mass of the washer = 8598kg/m^3 x 2.25x10^-6m^3 = 0.0189kg = 18.9 grams
6 0
3 years ago
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