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3 years ago

a car moving at 30.0 m/s slows uniformly to a speed of 10.0 m/s in a time of 5.00 s determine the. acceleration of the car

Physics

1 answer:

netineya [11]3 years ago

7 0

Answer: $-4m/s^{2}$

Explanation:

Acceleration $a$ is defined as the variation of Velocity $\Delta V$ in time $\Delta t$ :

$a=\frac{\Delta V}{\Delta t}$

In this case $\Delta V=10m/s - 30m/s$ and $\Delta t=5 s$ .

Therefore:

$a=\frac{10m/s - 30m/s}{5 s}$

$a=\frac{-20m/s}{5 s}$

$a=-4 m/s^{2}$ Note the negative sign indicates the car is slowing

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Bradley gets an x-ray at a radiology clinic that employs its own technologists and radiologists. Would the coder at the clinic r

KengaRu [80]

Answer:

Explanation:

If Bradley examination was done and interpreted in the same facility, the radiologist code is used example- procedure code 72100- Radiologic examination, spine, lumbosacral, 2 or 3 views is reported.

if the X-ray was taken by Dr X but Dr X does not read or interpret the image but forward it to the radiologist for initial report, then a 26- modifier is used. E.g A reports by the technologist would be, procedure code 72050-Radiologic examination, spine, cervical, 2 or 3

views or 72050- TC in certain situations and the consulting radiologist would report 72050-26.

if Bradley’s x-ray were sent to an independent radiologist for interpretation, then the procedure code 76140 is used in reporting.

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3 years ago

Which object has the most kinetic energy? a bus a car a plane a bicycle

loris [4]

Answer:I would guess a plane

Assuming they all Thad the same velocity....

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3 years ago

A small logo is embedded in a thick block of crown glass (n = 1.52), 4.70 cm beneath the top surface of the glass. The block is

harkovskaia [24]

The concept required to solve this problem is the optical relationship that exists between the apparent depth and actual or actual depth. This is mathematically expressed under the equations.

$d'w = d_w (\frac{n_{air}}{n_w})+d_g (\frac{n_{air}}{n_g})$

Where,

$d_g =$ Depth of glass

$n_w =$ Refraction index of water

$n_g =$ Refraction index of glass

$n_{air} =$ Refraction index of air

$d_w =$ Depth of water

I enclose a diagram for a better understanding of the problem, in this way we can determine that the apparent depth in the water of the logo would be subject to

$d'w = d_w (\frac{n_{air}}{n_w})+d_g (\frac{n_{air}}{n_g})$

$d'w = (1.7cm) (\frac{1}{1.33})+(4.2cm)(\frac{1}{1.52})$

$d'w = 4.041cm$

Therefore the distance below the upper surface of the water that appears to be the logo is 4.041cm

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3 years ago

A construction worker is pushing a 50.0-kg box with a force of 150.0 N to the right. If the box is moving at a constant velocity

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Yes omg yes I literally have the same question and need to find the answer

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2 years ago

If you have two uncertainties, and they are from two different sources and contribute to the uncertainty of a measurement, what

Darya [45]

The propagation errors we can find the uncertainty of a given magnitude is the sum of the uncertainties of each magnitude.

Δm = ∑ $| \frac{dm}{dx_i} | \ \Delta x_i$

Physical quantities are precise values of a variable, but all measurements have an uncertainty, in the case of direct measurements the uncertainty is equal to the precision of the given instrument.

When you have derived variables, that is, when measurements are made with different instruments, each with a different uncertainty, the way to find the uncertainty or error is used the propagation errors to use the variation of each parameter, keeping the others constant and taking the worst of the cases, all the errors add up.

If m is the calculated quantity, x_i the measured values and Δx_i the uncertainty of each value, the total uncertainty is

Δm = ∑ $| \frac{dm}{dx_i } | \ \Delta x_i$ | dm / dx_i | Dx_i

for instance:

If the magnitude is a average of two magnitudes measured each with a different error

m = $\frac{m_1+m_2}{2}$

Δm = | $\frac{dm}{dx_1}$ | Δx₁ + | $\frac{dm}{dx_2}$ | Δx₂

$\frac{dm}{dx_1}$ = ½

$\frac{dm}{dx_2}$ = ½

Δm = $\frac{1}{2}$ Δx₁ + ½ Δx₂

Δm = Δx₁ + Δx₂

In conclusion, using the propagation errors we can find the uncertainty of a given quantity is the sum of the uncertainties of each measured quantity.

Learn more about propagation errors here:

brainly.com/question/17175455

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2 years ago