From the starting depth to the surface, the vertical distance is 35 ft.
From the surface to the peak of the jump, the vertical distance is 27 ft.
From the peak of the jump to the surface, the vertical distance is 27 ft.
From the surface to the ending depth, the vertical distance is 18 ft.
Then the total vertical distance is ...
35 ft + 27 ft + 27 ft + 18 ft = 107 ft
Ok so the equation for momentum is:
v=p/m
So you would do:
7800/1200=6.5
So the answer is:
6.5 m/s
Hope this helps :)
Answer:
Explanation:
Given that
Force constant k=8.6N/m
Weight =64g=64/1000=0.064kg
Extension is 45mm=45/1000= 0.045m
It will have it highest spend when the Potential energy is zero
Therefore energy in spring =change in kinetic energy
Ux=∆K.e
½ke² = ½mVf² — ½mVi²
Initial velocity is 0, Vi=0m/s
½ke² = ½mVf²
½ ×8.6 × 0.045² = ½ ×0.064 ×Vf²
0.0087075 = 0.032 Vf²
Then, Vf² = 0.0087075/0.032
Vf² = 0.2721
Vf=√0.2721
Vf= 0.522m/s
The time it will have this maximum velocity?
Using equation of motion
Vf= Vi + gr
0.522= 0+9.81t
t=0.522/9.81
t= 0.0532sec
t= 53.2 milliseconds
Its actually A. I did the same question and A was the correct answer.
Answer:
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