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Temka [501]
3 years ago
6

Im just so confused on this how can dogs eat raw meat without getting sick but they cant eat chocolate but hoomanz cant eat raw

meat or they get sick but hoomanz can eat chocolate someone explain this to me :)
Physics
2 answers:
shutvik [7]3 years ago
8 0
Your question is just the same as “Is it called an orange because it’s orange or is it orange because it’s orange”?
SCORPION-xisa [38]3 years ago
3 0

Answer:

We're a different species.

Explanation:

Merry Christmas!

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For each of the problems below, you will need to draw a graph to find the solution.
Gelneren [198K]

Answer:

Final velocity (v) of an object equals initial velocity (u) of that object plus acceleration (a) of the object times the elapsed time (t) from u to v. Use standard gravity, a = 9.80665 m/s2, for equations involving the Earth's gravitational force as the acceleration rate of an object.

Explanation:

3 0
2 years ago
A constant force of 8N acting on an object displaces it through a distance of 3.0 m in the direction of force. Calculate work-do
sweet-ann [11.9K]

\blue{\bold{\underline{\underline{Answer:}}}}

  • \green{\tt{Work\:done=24\:J}}

\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}

\green{\underline{\bold{Given :}}} \\  \tt: \implies Constant \: force(F) = 8 \: N \\  \\ \tt: \implies Displacement(s) = 3 \: m \\  \\ \red{\underline{\bold{To \: Find : }}} \\  \tt:  \implies Work \: Done(W.D) = ?

• <u>According to given question</u> :

\green{ \star} \tt \:  \theta \:  = 0 \degree \:  \:  \:  \: (Angle \: between \: force \: and \: displacement) \\  \\  \bold{As \: we \: know \: that} \\  \tt:  \implies Work \: Done = FS \: cos  \: \theta \\  \\  \tt:  \implies Work \: Done = 8 \times 3 \times cos \:0 \degree \\  \\ \green{ \circ} \tt \: cos  \: 0 \degree = 1  \\  \\  \tt:  \implies Work \: Done =24 \times 1 \\  \\   \green{\tt:  \implies Work \: Done =24 \: J}

5 0
2 years ago
If temperature increases, then pressure __________.
lilavasa [31]
If the temperature increases, then pressure increases too. (T<span>he molecules in the gas move faster, exerting a greater force. This </span>increases t<span>he </span>pressure<span>.)</span>
6 0
3 years ago
The energy from 0.015 moles of octane was used to heat 250 grams of water. The temperature of the water rose from 293.0 K to 371
arsen [322]

Answer : The correct option is, (B) -5448 kJ/mol

Explanation :

First we have to calculate the heat required by water.

q=m\times c\times (T_2-T_1)

where,

q = heat required by water = ?

m = mass of water = 250 g

c = specific heat capacity of water = 4.18J/g.K

T_1 = initial temperature of water = 293.0 K

T_2 = final temperature of water = 371.2 K

Now put all the given values in the above formula, we get:

q=250g\times 4.18J/g.K\times (371.2-293.0)K

q=81719J

Now we have to calculate the enthalpy of combustion of octane.

\Delta H=\frac{q}{n}

where,

\Delta H = enthalpy of combustion of octane = ?

q = heat released = -81719 J

n = moles of octane = 0.015 moles

Now put all the given values in the above formula, we get:

\Delta H=\frac{-81719J}{0.015mole}

\Delta H=-5447933.333J/mol=-5447.9kJ/mol\approx -5448kJ/mol

Therefore, the enthalpy of combustion of octane is -5448 kJ/mol.

5 0
3 years ago
Three objects each with a mass of 10.0 kg are
Vera_Pavlovna [14]

Answer: F net=0

Explanation:

Its in the picture.

7 0
3 years ago
Read 2 more answers
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