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Nitella [24]
3 years ago
15

which principles of training refers o placing increased demands on the body? A. Specificity B. cross-training c.type D.overload

Physics
1 answer:
Anuta_ua [19.1K]3 years ago
5 0
Overload <<<<<<<<<<<<<<<<<<<<<<<<<<<<<,,,,,,,,
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Mashcka [7]
Composition and texture
6 0
3 years ago
Forces of 2 newtons and 3 newtons are acting on an object as shown in the drawing below. Calculate the resultant force in newton
Kipish [7]

Answer:

Hey mate

Your answer will be <u>5 N</u><u> </u><u>Upwards</u><u>.</u><u> </u>

I will explain this to you.

In the attachment we can see that there are two forces acting on the object from the same side. And we know that when force acts from the same direction. Then the total force

=> sum of all the forces in that particular direction.

I hope you got it :)

TheSarcasmic

5 0
3 years ago
2. A 75 kg runner accelerates from 0.00 m/s to 10.0 m/s in 1.5 seconds.
raketka [301]
A :-) A.a.) Given - u = 0.00 m/s
v = 10.0 m/s
t = 1.5 sec
m = 75 kg
Solution -
a = v - u by t
a = 10 - 0 by 1.5
a = 10 by 1.5
a = 6.6 m/s^2

A.b.) sorry ! I don’t no how to do this question
3 0
3 years ago
A dog and a cat sit on a merry-go-round. The dog sits 0.3 m from the center. The cat sits 1.5 m from the center. The whole merry
pochemuha

Answer:

hope that pic helps!! let me know!!

Explanation:

or this expert answers from expert

8 0
3 years ago
A race car traveling at 10 meters per second accelerates at 1.5 meters per second squared while moving a distance of 600 meters.
Mekhanik [1.2K]

Answer:

Explanation:

Givens

vi = 10 m/s

a = 1.5 m/s^2

d = 600 m

vf = ?

Formula

vf^2 = vi^2 + 2*a*d

Solution

vf^2 = 10^2 + 2*1.5 * 600

vf^2 = 100 + 1800

vf^2 = 1900

sqrt(vf^2) = sqrt(1900)

vf = 43.59 m/s

7 0
3 years ago
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