which principles of training refers o placing increased demands on the body? A. Specificity B. cross-training c.type D.overload

In a city park a nonuniform wooden beam 5.00 m long is suspended horizontally by a light steel cable at each end. The cable at t

DanielleElmas [232]

Answer:

Explanation:

System of forces in balance

ΣFx = 0

ΣFy = 0

∑MA = 0

MA = F*d

Where:

∑MA : Algebraic sum of moments in the the point (A)

MA : moment in the point A ( N*m)

F : Force ( N)

d : Horizontal distance of the force to the point A ( N*m

Forces acting on the beam

T₁ = 620 N : Tension in cable 1 ,at angle of 30° with the vertical on the left

T₂ : Tension in cable 2, at angle of 50.0° with the vertical on the right.

W : Weight of the beam

x-y T₁ and T₂ components

T₁x= 620*sin30° = 310 N

T₁y= 620*cos30° = 536.94 N

T₂x= T₂*sin50°

T₂y= T₂*cos50°

Calculation of the T₂

ΣFx = 0

T₂x-T₁x = 0

T₂x=T₁x

T₂*sin50° = 310 N

T₂ = 310 N /sin50°

T₂ = 404.67 N

Calculation of the W

ΣFy = 0

T₂y+T₁y-W = 0

(404.67) *cos50° + 536.94 = W

W= 260.12+ 536.94

W= 797.06 N

Location of the center of gravity of the beam

∑MA = 0 , point (A) (point where the cable 2 of the right is located on the beam)

T₁y(5)-W(d) = 0

T₁y(5) = W(d)

d = T₁y(5)/W

d = 536.94(5) / 797.06

d = 3.37m

The center of gravity is located at 3.37m measured from the right end of the beam

5 0

3 years ago

Doug, who runs track for his high school, was challenged to a race by his younger brother, matt. Matt started running first, and

eduard

The speed of Matt is 10 mph.

Doug runs 2 miles an hour faster than Matt, so let Matt’s speed equal x miles per hour. Then Doug’s speed equals x + 2 miles per hour. Each lap is one-quarter of a mile, so Doug runs 1.5 miles in the time it takes Matt to run 1.25 miles.

Rate of Matt is x

Rate of Dough is (x + 2)

Time taken by Matt is 1.25/x

Time taken by Dough is 1.25/(x + 2)

Distance covered by Matt is 1.25

Distance covered by Dough is 1.5

Dough and Matt took the same amount of time from the time Doug started, so make an equation by setting the two times in the chart equal to each other, and then solve for x:

$\frac{1.5}{(x + 2)}$ = $\frac{1.25}{x}$

1.5x = 1.25(x + 2)

1.5x = 1.25x + 2.5

0.25x = 2.5

x = 10

So Matt ran at 10 miles per hour.

To know more about time, speed and distance, visit: brainly.com/question/26046491

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7 0

1 year ago

What type of sound is produced when string vibrates rapidly?

amid [387]

The faster a string vibrates, the higher frequency sound it produces,
and the higher the pitch is that we hear.

8 0

3 years ago

An astronaut circling the earth at an altitude of 400 km is horrified to discover that a cloud of space debris is moving in the

elena-14-01-66 [18.8K]

One of the essential concepts to solve this problem is the utilization of the equations of centripetal and gravitational force.

From them it will be possible to find the speed of the body with which the estimated time can be calculated through the kinematic equations of motion. At the same time for the calculation of this speed it is necessary to clarify that this will remain twice the ship, because as we know by relativity, when moving in the same magnitude but in the opposite direction, with respect to the ship the debris will be double speed.

By equilibrium the centrifugal force and the gravitational force are equal therefore

$F_c = F_g$