Answer:
232.9m³ (Option b. is the closest answer)
Explanation:
Given:
Air pressure in the lab before the storm, P₁ = 1.1atm
Air volume in the lab before the storm, V₁ = 180m³
Air pressure in the lab during the storm P₂ = 0.85atm
Air volume in the lab before the storm, V₂ = ?
Applying Boyle's law: P₁V₁ = P₂V₂ (at constant temperature)
V₂ = 232.9m³
The air volume in the laboratory that would expand in order to make up for the large pressure difference outside is 232.9m³
Near Earth's surface, gravitational acceleration is approximately 9.81 m/s2, which means that, ignoring the effects of air resistance, the speed of an object falling freely will increase by about 9.81 metres per second every second.
A charged particle moving in a magnetic field experiences a force equal to:
Thus, the magnitude of the force that the proton experiences is given by:
The magnetic field is perpendicular to the proton's velocity, therefore, we have 
. Replacing the given values, we obtain:
<span>On the scale the only external forces are the man's weight acting downwards and the normal force which the scale exerts back to support his weight.
So F = Ma = mg + Fs
The normal force Fs (which is actually the reading on the scale) = Ma + Mg
But a = 0
So Fs = Mg which is just his weight.
Fs = 75 * 9.8 = 735N</span>
