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vagabundo [1.1K]
3 years ago
5

Sodium reacts with chlorine gas to form sodium chloride. Write a balanced chemical equation for the reaction, and find the mass

of chlorine gas that will react with 96.6 g of sodium.
Chemistry
2 answers:
weqwewe [10]3 years ago
8 0
2Na + Cl2 ⇒ 2NaCl

96.6g Na ((1 mole Na)/(22.99 g Na))((1 mole Cl2)/(2 mole Na))((70.9 g Cl2)/(1 mole Cl2))=149 g Cl2

Bess [88]3 years ago
4 0
Chemical equation:
2 Na + Cl _{2}   -\ \textgreater \  2NaCl
M ( Na ) = 23 g/moles   ( 2 moles Na = 46 g )
M ( Cl 2 ) = 71 g/moles  ( 1 mole Cl 2 = 71 g )
so Na needs more Cl 2 to react;
96  : x = 46 : 71
46 x = 6816
x = 6816 : 46
x = 148.17 g
Answer: the mass of chlorine gas is 148.17 g.
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Answer:

The correct answer is 574.59 grams.

Explanation:

Based on the given information, the number of moles of NH₃ will be,  

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The Kb of ammonia given is 1.8 * 10^-5. Now pKb = -logKb,  

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Based on Henderson equation:  

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pOH = pKb + [NH₄⁺]/[NH₃]

5.47 = 4.74 + log ([NH₄⁺]/[NH₃])

log([NH₄⁺]/[NH₃]) = 5.47-4.74 = 0.73

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[NH₄⁺ = 5.37 × 2 mol = 10.74 mol

Now the mass of dry ammonium chloride required is,  

mass of NH₄Cl = 10.74 mol × 53.5 g/mol

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