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vagabundo [1.1K]
3 years ago
5

Sodium reacts with chlorine gas to form sodium chloride. Write a balanced chemical equation for the reaction, and find the mass

of chlorine gas that will react with 96.6 g of sodium.
Chemistry
2 answers:
weqwewe [10]3 years ago
8 0
2Na + Cl2 ⇒ 2NaCl

96.6g Na ((1 mole Na)/(22.99 g Na))((1 mole Cl2)/(2 mole Na))((70.9 g Cl2)/(1 mole Cl2))=149 g Cl2

Bess [88]3 years ago
4 0
Chemical equation:
2 Na + Cl _{2}   -\ \textgreater \  2NaCl
M ( Na ) = 23 g/moles   ( 2 moles Na = 46 g )
M ( Cl 2 ) = 71 g/moles  ( 1 mole Cl 2 = 71 g )
so Na needs more Cl 2 to react;
96  : x = 46 : 71
46 x = 6816
x = 6816 : 46
x = 148.17 g
Answer: the mass of chlorine gas is 148.17 g.
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Answer:

neutral pH or neutral solution

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3 years ago
Which of the following statements is generally TRUE?
Vesnalui [34]

The correct answer is option d, that is, the solubility of a solid is highly dependent on temperature.  

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3 years ago
On the basis of the information above, a buffer with a pH = 9 can best be made by using
telo118 [61]

Answer:

D H2PO4– + HPO42–

Explanation:

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\mathbf{pka (H_3PO_4) = -log (7\times 10^{-3} )=2.2}

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3 0
3 years ago
Which is the correct number of moles of NO that is produced from 13.2 moles of oxygen
Oksanka [162]
<h3>Answer:</h3>

10.6 mol NO

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced] 4NH₃ + 5O₂ → 4NO + 6H₂O

[Given] 13.2 mol O₂

<u>Step 2: Identify Conversions</u>

[RxN] 5 mol O₂ → 4 mol NO

<u>Step 3: Stoich</u>

  1. [DA] Set up:                                                                                                     \displaystyle 13.2 \ mol \ O_2(\frac{4 \ mol \ NO}{5 \ mol \ O_2})
  2. [DA] Multiply/Divide [Cancel out units]:                                                         \displaystyle 10.56 \ mol \ NO

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

10.56 mol NO ≈ 10.6 mol NO

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