Answer:
- <u>Tellurium (Te) and iodine (I) are two elements </u><em><u>next to each other that have decreasing atomic masses.</u></em>
Explanation:
The <em>atomic mass</em> of tellurium (Te) is 127.60 g/mol and the atomic mass of iodine (I) is 126.904 g/mol; so, in spite of iodine being to the right of tellurium in the periodic table (because the atomic number of iodine is bigger than the atomic number of tellurium), the atomic mass of iodine is less than the atomic mass of tellurium.
The elements are arranged in increasing order of atomic number in the periodic table.
The atomic number is equal to the number of protons and the mass number is the sum of the protons and neutrons.
The mass number, except for the mass defect, represents the atomic mass of a particular isotope. But the atomic mass of an element is the weighted average of the atomic masses of the different natural isotopes of the element.
Normally, as the atomic number increases, you find that the atomic mass increases, so most of the elements in the periodic table, which as said are arranged in icreasing atomic number order, match with increasing atomic masses. But the relative isotope abundaces of the elements can change that.
It is the case that the most common isotopes of tellurium have atomic masses 128 amu and 130 amu, whilst most common isotopes of iodine have an atomic mass 127 amu. As result, tellurium has an average atomic mass of 127.60 g/mol whilst iodine has an average atomic mass of 126.904 g/mol.
This
electronic transition would result in the emission of a photon with the highest
energy:
4p
– 2s
<span>This
can be the same with the emission of 4f to 2s which would emit energy in the
visible region. The energy in the visible region would emit more energy than in
the infrared region which makes this emission to have the highest energy.</span>
Answer:
0.600 g/cm³
Explanation:
Step 1: Given data
- Height of the cylinder (h): 6.62 cm
- Diameter of the cylinder (d): 2.34 cm
- Mass of the cylinder (m): 17.1 g
Step 2: Calculate the volume of the cylinder
First, we have to determine the radius, which is half of the diameter.
r = d/2 = 2.34 cm/2 = 1.17 cm
Then, we use the formula for the volume of the cylinder.
V= π × r² × h
V= π × (1.17 cm)² × 6.62 cm
V = 28.5 cm³
Step 3: Calculate the density (ρ) of the sample
The density is equal to the mass divided by the volume.
ρ = m/V
ρ = 17.1 g/28.5 cm³
ρ = 0.600 g/cm³
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