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Yuliya22 [10]
3 years ago
8

Which one of the following steps could be used as a shortcut method to multiply 12 by 50?

Mathematics
2 answers:
tatiyna3 years ago
6 0
A, I think.  I could be wrong though.
MissTica3 years ago
6 0
The answer is C because 12*100 is 1200. 1200/2 is 600 which is also the answer to 12*50
You might be interested in
Prove that if {x1x2.......xk}isany
Radda [10]

Answer:

See the proof below.

Step-by-step explanation:

What we need to proof is this: "Assuming X a vector space over a scalar field C. Let X= {x1,x2,....,xn} a set of vectors in X, where n\geq 2. If the set X is linearly dependent if and only if at least one of the vectors in X can be written as a linear combination of the other vectors"

Proof

Since we have a if and only if w need to proof the statement on the two possible ways.

If X is linearly dependent, then a vector is a linear combination

We suppose the set X= (x_1, x_2,....,x_n) is linearly dependent, so then by definition we have scalars c_1,c_2,....,c_n in C such that:

c_1 x_1 +c_2 x_2 +.....+c_n x_n =0

And not all the scalars c_1,c_2,....,c_n are equal to 0.

Since at least one constant is non zero we can assume for example that c_1 \neq 0, and we have this:

c_1 v_1 = -c_2 v_2 -c_3 v_3 -.... -c_n v_n

We can divide by c1 since we assume that c_1 \neq 0 and we have this:

v_1= -\frac{c_2}{c_1} v_2 -\frac{c_3}{c_1} v_3 - .....- \frac{c_n}{c_1} v_n

And as we can see the vector v_1 can be written a a linear combination of the remaining vectors v_2,v_3,...,v_n. We select v1 but we can select any vector and we get the same result.

If a vector is a linear combination, then X is linearly dependent

We assume on this case that X is a linear combination of the remaining vectors, as on the last part we can assume that we select v_1 and we have this:

v_1 = c_2 v_2 + c_3 v_3 +...+c_n v_n

For scalars defined c_2,c_3,...,c_n in C. So then we have this:

v_1 -c_2 v_2 -c_3 v_3 - ....-c_n v_n =0

So then we can conclude that the set X is linearly dependent.

And that complet the proof for this case.

5 0
3 years ago
During one snowy month a kentucky school held classes 9/11 of possible the school days if there are 22 possible school days how
SOVA2 [1]
This question isn't phrased correctly, but I will assume it's asking about common denominators with fractions.

9/11 1/22

18/22 1/22

18 school days.
5 0
3 years ago
Find the 5th term of the sequence which has a first of 1 and a common ratio of 2.3
sveticcg [70]
Hello : 

the nth term is :  An =A1 × r^(n-1)

A1 = 1      r = 2.3     n = 5

 A5 =1 × (2.3)^(5-1)=27.9841


3 0
3 years ago
3. Find two possible lengths for CD if C, D, and E
Kaylis [27]

Given :

C, D, and E  are col-linear, CE = 15.8 centimetres, and DE=  3.5 centimetres.

To Find :

Two possible lengths for CD.

Solution :

Their are two cases :

1)

When D is in between C and E .

.                   .           .

C                  D          E

Here, CD = CE - DE

CD = 15.8 - 3.5 cm

CD = 12.3 cm

2)

When E is in between D and C.

.       .                .

D      E              C

Here, CD = CE + DE

CD = 15.8 + 3.5 cm

CD = 19.3 cm

Hence, this is the required solution.

3 0
3 years ago
If the dimension of a square is 3 1/2 what would the perimeter be?
Eduardwww [97]
It would be 3 because in a half means like cut so what is in the middle between 2 and 4? 3 so that is correct



6 0
3 years ago
Read 2 more answers
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