The concentration of the FeSO4 solution in molarity would be 0.4356
The concentration can be derived first by writing out the balanced equation of the reaction:
From the balanced equation: for every 1 mole of KMnO4, 5 moles of FeSO4 is needed for complete oxidation.
Recall that: mole = molarity x volume
Mole of KMnO4 needed = 0.1327 x 0.01642
= 0.002179 mole
1 mole KMnO4 = 5 mole FeSO4
0.002178 mole = 5 x 0.002178/1
= 0.01089 moles of FeSO4
Molarity of FeSO4 = mole/volume
= 0.01089/0.025
= 0.4356 M
More on the calculation of molarity of solutions can be found here: brainly.com/question/16587536
It is colorless and oderless is a physical property by telling what color.
Sodium is categorized as a B. Element.
Answer : The percent by mass of the solution is 7.81 %
Explanation : Given,
Mass of NaCl = 8.75 g
Mass of solution = 112.0 g
Now we have to determine the percent by mass of the solution.

Putting values in above equation, we get:

Therefore, the percent by mass of the solution is 7.81 %