We do a heat balance to solve this:
(m cp ΔT)water = -(m cp ΔT)metal
100.8 (4.18) (27 - 22) = -65 (cp)(27-100)
cp = 100.8 (4.18) (27 - 22) / (-65 (27-100))
cp = 0.44 J/ (°C × g)
The specific heat of the metal is 0.44 J/ (°C × g)
The answer is D; Mass and Velocity
Hmm well thinking of how amperes are generated it should be true
An induced current is a conducting loop that is exposed to a changing magnetic field. And it is knows as induced current
Answer:
D. when the number of moles of acid is exactly equal to the number of moles of base.
Explanation:
<em>Regarding options A. and E</em>., pKa and pKb would only be taken into consideration if the titrations were of <em>weak</em> acids and bases. However it is possible to have a titration of monoprotic acids and bases with strong acids and bases.
Another way of looking at the answer is identifying <em>which one best describes the equivalence point</em>.
