Answer:
49.4 g Solution
Explanation:
There is some info missing. I think this is the original question.
<em>A chemistry student needs 20.0g of acetic acid for an experiment. He has 400.g available of a 40.5 % w/w solution of acetic acid in acetone. </em>
<em>
Calculate the mass of solution the student should use. If there's not enough solution, press the "No solution" button. Round your answer to 3 significant digits.</em>
<em />
We have 400 g of solution and there are 40.5 g of solute (acetic acid) per 100 grams of solution. We can use this info to find the mass of acetic acid in the solution.
Since we only need 20.0 g of acetic acid, there is enough of it in the solution. The mass of solution that contains 20.0 g of solute is:
Answer:
<u>Question</u><u> </u><u>1</u><u> </u><u>:</u>
• A compound is ionic if it is made up of a metal or a cation (+) and a non metal or anion (-)
<u>Question</u><u> </u><u>2</u><u> </u><u>:</u>
• While naming ionic compounds, follow the formula → "metal" + "non-metal ending with <em>ide</em><em> </em>"
• i.e; Sodium Chloride:
<u>Question</u><u> </u><u>3</u><u> </u><u>:</u>
• The answer above that question is perfect.
<u>Question</u><u> </u><u>4</u><u> </u><u>:</u>
1 atom → Mono. But it is highly recommended to ignore it
2 atoms → DI
3 atoms → TRI
4 atoms → TETRA
5 atoms → PENTA ( such as pentaoxide )
7 atoms → HEPTA ( such as heptaoxide )
<u>Question</u><u> </u><u>5</u><u> </u><u>and</u><u> </u><u>6</u><u>:</u>
Are perfectly answered.
I believe the correct answer from the choices listed above is option D. The molar mass of <span>Mg(ClO2)2 is obtained by adding the atomic masses of each atom in the compound and the result is 159.21 g per mole. Hope this answers the question. Have a nice day.</span><span />
I think it’s always gonna be 2
to counteract the sourness of the acids. just did this assignment so i know this is correct
