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Alla [95]
3 years ago
12

What is 3 divided by 31

Mathematics
2 answers:
Basile [38]3 years ago
8 0
0.09677419354 = 3 divided by 31
ziro4ka [17]3 years ago
3 0
. 3 divided by 31 equals: 0. 096774
You might be interested in
Which sum does not equal ?<br> 7/8
Drupady [299]

The sum which is not equal to 7/8 is 7/8 +7/8 = 14/8

Given,

a) 2/8 + 5/8 = 7/8 which is equal to 7/8.

Therefore, option a) is incorrect.

b) 1/8 + 6/8 = 7/8, which  is also equal to 7/8.

Option b) is also incorrect.

c) 7/8 + 7/8 = 14/8 , which is not equal to 7/8.

Hence option c) is correct.

d) 3/8 + 4/8 = 7/8, which is equal to 7/8.

Option d) is also incorrect.

Hence option c) is correct as it matches the conditions of the question.

7/8 + 7/8 = 14/8 is not equal to 7/8.

To learn more about the sum, visit: brainly.com/question/2059515

#SPJ9

7 0
2 years ago
Anyone know this ill give brainliest pls help
Katena32 [7]
Answers are 7, 5, 3, 1
6 0
3 years ago
Read 2 more answers
How do you simplify the equation useing like terms: 8r+12p-7-3p
stiks02 [169]

Answer:

8r+9p-7

Step-by-step explanation:

12p-3p=9p

8r+9p-7

7 0
3 years ago
What is the square root of y^3
tia_tia [17]

Answer:

y^{\frac{3}{2}

Step-by-step explanation:

Let m=\sqrt{y^3}

m=(y^3)^{\frac{1}{2}}\\\\m=y^{3\times \frac{1}{2}}\ \ \ \ \ \ \ \ \ [as\ (x^a)^b=x^{ab}]\\\\m=y^{\frac{3}{2}

7 0
3 years ago
Which statements about the local maximums and minimums for the given function are true? Choose three options.
Nostrana [21]

Answer:

Over the interval [2, 4], the local minimum is –8.

Over the interval [3, 5], the local minimum is –8.

Over the interval [1, 4], the local maximum is 0.

Step-by-step explanation:

The true statements are:

Over the interval [2, 4], the local minimum is –8.

Over the interval [3, 5], the local minimum is –8.

Over the interval [1, 4], the local maximum is 0.  

Lets discuss each option one by one:

Over the interval [1, 3], the local minimum is 0

This is a false statement. Look at the graph. The minimum point given is (3.4,-8). Therefore the local minimum is -8 not 0

Over the interval [2, 4], the local minimum is –8.

This statement is true because the given minimum point is(3.4, -8). Thus the  local minimum is -8 which is true

Over the interval [3, 5], the local minimum is –8.

According to the given minimum point, the local minimum  is -8 which is true

Over the interval [1, 4], the local maximum is 0.

Look at the graph. The maximum point given is (2,0). Thus this statement is true because local maximum is 0.

Over the interval [3, 5], the local maximum is 0.

This is a false statement because there is no maximum point

8 0
3 years ago
Read 2 more answers
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