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nikdorinn [45]
4 years ago
6

The ability to conduct electricity in the solid state is a characteristic of metallic bonding. This characteristic is best expla

ined by the presence of________.
Chemistry
1 answer:
telo118 [61]4 years ago
4 0

Answer:

The ability to conduct electricity in the solid state is a characteristic of metallic bonding. This characteristic is best explained by the presence of cations

Explanation:

First of all we should know what are the valence electrons. These are the ones that are  involved in the formation of chemical bonds  (for representative elements, blocks s and p)

A cation is an atom which has lost an electron (+ charge).

The metalic atoms lose all the valence electrons, as these atoms remain charged, that is why they are capable of conducting electricity.

For example:

K (s) →  K⁺  +  1e⁻

In the opposite side, the anions are formed when the non metallic elements win electrons to complete the octet rule.

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Which statement is true about the speed of light
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3 years ago
How many moles of ammonia can you make from 0.37 moles of H2?
igomit [66]

Answer:

0.123 moles of ammonia, can be produced

Explanation:

First of all, we need to determine the reaction:

Ammonia is produced by the reaction of hydrogen and nitrogen.

3H₂(g) + N₂(g) → 2NH₃(g)

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6 0
4 years ago
Nicotine, a component of tobacco, is composed of c, h, and n. a 4.200-mg sample of nicotine was combusted, producing 11.394 mg o
Rudiy27

Answer:

            Empirical Formula  =  C₅H₇N₁

Solution:

Data Given:

                      Mass of Nicotine  =  4.20 mg  =  0.0042 g

                      Mass of CO₂  =  11.394 mg  =  0.011394 g

                      Mass of H₂O  =  3.266 mg  =  0.003266 g

Step 1: Calculate %age of Elements as;

                      %C  =  (mass of CO₂ ÷ Mass of sample) × (12 ÷ 44) × 100

                      %C  =  (0.011394 ÷ 0.0042) × (12 ÷ 44) × 100

                      %C  =  (2.7128) × (12 ÷ 44) × 100

                      %C  =  2.7128 × 0.2727 × 100

                      %C  =  73.979 %


                      %H  =  (mass of H₂O ÷ Mass of sample) × (2.02 ÷ 18.02) × 100

                      %H  =  (0.003266 ÷ 0.0042) × (2.02 ÷ 18.02) × 100

                      %H  =  (0.7776) × (2.02 ÷ 18.02) × 100

                      %H  =  0.7776 × 0.1120 × 100

                      %H  =  8.709 %


                      %N  =  100% - (%C + %H)

                      %N  =  100% - (73.979 % + 8.709%)

                      %N  =  100% - 82.688%

                      %N  =  17.312 %

Step 2: Calculate Moles of each Element;

                      Moles of C  =  %C ÷ At.Mass of C

                      Moles of C  = 73.979 ÷ 12.01

                     Moles of C  =  6.1597 mol


                      Moles of H  =  %H ÷ At.Mass of H

                      Moles of H  = 8.709 ÷ 1.01

                      Moles of H  =  8.6227 mol


                      Moles of N  =  %N ÷ At.Mass of O

                      Moles of N  = 17.312 ÷ 14.01

                      Moles of N  =  1.2356 mol

Step 3: Find out mole ratio and simplify it;

                C                                        H                                     N

            6.1597                               8.6227                             1.2356

     6.1597/1.2356                  8.6227/1.2356                 1.2356/1.2356

               4.985                             6.978                                   1

             ≈ 5                                      ≈ 7                                     1

Result:

        Empirical Formula  =  C₅H₇N₁

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Answer:

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Explanation:

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