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KiRa [710]
3 years ago
12

The city council is considering discussing whether or not to put fluoride in the city's water supply. Many other towns add it al

ready, but your town wants to research the topic before they make a decision. Which would be the best group for them to ask for information on the topic?
citizens from the town who are interested in the topic
the company that supplies fluoride
a report from an independent scientific research firm
citizens from another town that currently add fluoride to their water
Physics
2 answers:
umka2103 [35]3 years ago
8 0
They should look for <span>a report from an independent scientific research firm,
even if they have to pay for it.

In preparing its report, the firm would have already surveyed many of the </span>
<span>citizens from several other towns that currently add fluoride to their water,
plus a lot of other relevant medical research on the subject.</span>
Over [174]3 years ago
5 0

''a report from an independent scientific research firm'' would be the best answer

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The medium through which a mechanical wave passes can be a solid, liquid, or gas. Properties of a wave change when it moves from
Tpy6a [65]

Answer:

Option A

Explanation:

Mechanical waves requires some medium to travel through. They travel faster in the dense medium as compared to a free medium.

The speed of a mechanical wave is fastest in the solid medium and the slowest in the gaseous medium. Hence, as the wave traverses from gaseous medium to the solid medium, its speed increases.

Thus, option A is correct

3 0
3 years ago
A 12kg cheetah accelerates 24 m/s". What is the force the cheetah needed to run?
Kobotan [32]

Answer:

288N

Explanation:

Given parameters:

Mass of Cheetah = 12kg

Acceleration  = 24m/s²

Unknown:

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The force needed by the Cheetah to run is the net force.

According to Newton's law;

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7 0
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Which causes the thermocline?
Igoryamba
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4 0
3 years ago
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expeople1 [14]

Explanation:

Given that,

Wavelength of the light, \lambda=691\ nm=691\times 10^{-9}\ m

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\theta=0.104^{\circ}

(b) Slit width, a=3.8\times 10^{-6}\ m

The angle that locates the first dark fringe is given by :

sin\theta=\dfrac{\lambda}{a}

sin\theta=\dfrac{691\times 10^{-9}}{3.8\times 10^{-6}}

\theta=10.47^{\circ}

Hence, this is the required solution.

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