That would be t<span>he law of conservation of energy.</span>
The hot discharge gas from the refrigerant compressor is normally cooled and condensed at high pressure. This is then passed through an 'Expansion' valve which decreases the pressure to a low level causing expansion of the refrigerant liquid.
<span>The liquid partially vapourises causing a 'Joule's/Thompson' refrigeration effect' which decreases temperature of the refrigerant which then passes to an evaporator coil in the air circulation system of the building. </span>
<span>In the evaporator coil, the heat exchange between the cold refrigerant and the warm air of the building, vaporises and heats the refrigerant which returns to the compressor. </span>
<span>The cycle is repeated until the air temperature reaches the thermostat set-point and switches off the system. </span>
<span>As a Heat pump, the hot refrigerant gas is not evaporating and condensing. </span>
<span>From the compressor discharge, the hot gas is by-passing the cooler/condenser unit and the expansion valve and passes directly to the 'evaporator' coils but now, as the heating medium for the air circulation system where it's cooled by the heat exchange between the hot gas and the cooler air in the building and returns to the compressor in a continuous cycle. </span>
<span>A Thermostat in the system starts and stops the compressor motor according to the heat or cool temperature settings.</span>
Answer:
The second one is a function. {(-8, -2), (7, -2),(-9,2), (0,0)
Explanation:
Its because the y-value is repeated twice.
Hope it helps.
The pressure at the depth h in the ocean is given by (Stevin's law)
where
is the atmospheric pressure
and
is the pressure exerted by the column of water of height h=4267 m, with
being the water density and
.
Substituting, we find
We want to convert this into atmospheres: we know that 1 atm corresponds to the atmospheric pressure at sea level, so
, therefore we just need to divide by this number:
At 100 km/hr, the car's kinetic energy is
KE = (1/2) (mass) (speed)²
KE = (1/2) (1575 kg) ( [100 km/hr] x [1000 m/km] x [1 hr/3600 sec] )²
KE = (787.5 kg) (27.78 m/s)²
KE = 607,639 Joules
In order to deliver this energy in 2.9 seconds, the engine must supply
(607,639 J / 2.9 sec) = 209,531 watts
<em>Power = 281 HP</em>
