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fgiga [73]
3 years ago
7

Number 14.587020 to 4 significant digits.

Physics
2 answers:
Sindrei [870]3 years ago
6 0
14.58? All numbers are significant except 0 unless 0 is between two numbers 
Charra [1.4K]3 years ago
5 0
I totally agree with @<span>Boomitstaylorr.................</span>
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What is the acceleration of a 600,000 kg freight train, if each of itsthree engines can provide 100,000 n of force?
sergey [27]

The acceleration of a 600,000 kg freight train, if each of its three engines can provide 100,000N of force is 0.167m/s².

<h3>How to calculate acceleration?</h3>

The acceleration of a freight train can be calculated using the following formula:

Force = mass × acceleration

According to this question, a 600,000kg freight train can produce 100,000N of force. The acceleration is as follows:

100,000 = 600,000 × a

100,000 = 600,000a

a = 0.167m/s²

Therefore, the acceleration of a 600,000 kg freight train, if each of its three engines can provide 100,000N of force is 0.167m/s².

Learn more about acceleration at: brainly.com/question/12550364

#SPJ1

6 0
1 year ago
A circular 10-turn coil with a radius of 5.0 cm carries a current of 5 A. It lies in the xy plane in a uniform magnetic field =
Tju [1.3M]

Answer:

U = – 0.12J

Explanation:

Given N = 10 turns, I = 5A, r = 5×10-²m

B^ = 0.05 T iˆ+ 0.3 T kˆ

Magnitude of the magnetic field vector B = √(0.05²+0.3²) = 0.304T

Area = πr² = π(5×10-²)² = 7.85×10-³m²

Magnetic moment μ = NIA

μ = 10×5×7.85×10-³ = 0.3925Am²

U = -μ•B = –0.3925×0.304 = –0.12J

The sign is negative because the magnetic moment is aligned with the magnetic field.

3 0
2 years ago
An object has a momentum of 4,000 kg-m/s and a mass of 115 kg. It crashes into another object that has a mass of 100 kg, and the
ANTONII [103]

Answer:

18.60  m/s

Explanation:

Original momentum = mv = 4000        with m = 115    

after collision   m = 115 + 100 = 215 kg

  but the total momentum is still the same (conserved)

          4000 = 215 v      shows v = 18.60 m/s

4 0
2 years ago
A ball is kicked from the ground into the air at a velocity of 3 m/s at an angle 35° above the horizontal and hits the ground so
Dennis_Churaev [7]

Answer:2.45 m/s

Explanation:

Given

Launch velocity(u)=3 m/s

launch angle=35^{\circ}

as the vertical velocity first decreasing to zero and then increases to original value so its avg is zero .

v_{avg}=\frac{displacement}{time}

v_{avg}=\frac{Range}{time}

v_{avg}=\frac{u\cos \theta \times t}{t}

thus v_{avg}=\frac{3\cos 35\times t}{t}

v_{avg}=3\cos 35=2.45 m/s

8 0
3 years ago
What type of lens is used to correct nearsightedness.
Stella [2.4K]

Answer:

Concave lenses are used in eyeglasses that correct myopia or nearsightedness.

5 0
2 years ago
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