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liberstina [14]
3 years ago
7

How do I find the function that corresponds to this graph?

Mathematics
1 answer:
Vikentia [17]3 years ago
4 0
Th graph of ln x is same shape as this excepts its pass through the point (1,0) and has an asymptote  x = 0

THis graph is the graph of ln x moved 1 unit to the left so its 

y = ln (x + 1)
You might be interested in
2. Solve the equation p2 + 6p = 1 by completing the square method. Show your work.
goldfiish [28.3K]

Answer:

p=0.125

Step-by-step explanation:

2p+6p=1

Add like terms

8p=1

Divide both sides by 8 to get p by itself

8p/8=1/8

p=0.125

7 0
3 years ago
the rule for being the nth item in a certain sequence is n(n+1)/2. what is the 4th term in this sequence ? a.) 4b.)10c.)16d.)20
abruzzese [7]

The 4th term of the sequence can be determined as,

\begin{gathered} a_n=\frac{n(n+1)}{2} \\ a_4=\frac{4(4+1)}{2} \\ a_4=10 \end{gathered}

Thus, option (b) is correct.

3 0
1 year ago
Suppose that the division N/5 leaves a remainder of 4, and the division N/2 leaves a remainder of 1, what is the ones digit on N
Tju [1.3M]

Since <em>N</em>/2 leaves a remainder, <em>N</em> must be odd and ends with 1, 3, 5, 7, or 9.

<em>N</em>/5 also leaves a remainder, so <em>N</em> is not divisible by 5, so it does not end in 5.

The only correct choice is then 9, since

1 = 0•5 + 1 and 1 = 0•2 + 1

3 = 0•5 + 3 and 3 = 1•2 + 1

7 = 1•5 + 2 and 7 = 3•2 + 1

9 = 1•5 + <u>4</u> and 9 = 4•2 + <u>1</u>

<u />

Alternatively, the given information is equivalent to saying

N\equiv 4\pmod5\\\\N\equiv1\pmod2

Then you can use the Chinese remainder theorem to find <em>N</em>.

7 0
3 years ago
Find the area of the shaded region. Round the the nearest tenth.
Brums [2.3K]

Answer:

226.084 sq.m.

Step-by-step explanation:

Radius of circle = 18.6 cm

Area of sector = \frac{\theta}{360^{\circ} }\pi r^2

Area of sector = \frac{123}{360} \times 3.14 \times (18.6)^2

Area of sector = 371.157 m^2

Area of triangle = \frac{1}{2} \times a \times b \times Sin x

a = OA = radius = 18.6 cm

b = OB = radius = 18.6 cm

x =123 °

Substitute the values in the formula

Area of triangle = \frac{1}{2} \times 18.6 \times 18.6 \times Sin 123

Area of triangle = 145.073 m^2

So, Area of shaded region = Area of sector - Area of triangle

                                            =371.157 m^2-145.073 m^2

                                            =226.084 m^2

Hence the area of the shaded region is 226.084 sq.m.

5 0
3 years ago
P(x)=5x^2-3x+7(x=1)<br> Pls
kramer

Answer:

9

Step-by-step explanation:

Given

p(x) = 5x² - 3x + 7 ← substitute x = 1

p(1) = 5(1)² - 3(1) + 7 = 5(1) - 3(1) + 7 = 5 - 3 + 7 = 9

4 0
3 years ago
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