Question

A 1.0 kg block is placed against an ideal spring with spring constant 800 N/m and initially compressed 0.20 m. The spring and block lie on a frictionless 30 degree incline. The system is then released from rest and the block slides up the incline. How far from the release point does the mass slide before momentarily coming to rest (reaching its maximum height)?

Answer 1

Answer:

the release will be at 3.266 m distance

Explanation:

mass = 1 Kg

spring constant (k) = 800 N/m

initial compression = 0.20 m

θ = 30⁰

$U= \dfrac{1}{2}kx^2\\U= \dfrac{1}{2}800\times 0.2^2\\U= 16 J$

$U=mgh\\h=\dfrac{U}{mg}\\h=\dfrac{16}{1 \times 9.8}\\h = 1.633m$

$d=\dfrac{h}{sin \theta}\\d=\dfrac{1.633}{sin 30}\\\\d= 3.266m$

hence the release will be at 3.266 m distance.