Answer:
The object accelerates downward at 4 m/s² since the tension on the rope is less than weight of the object.
Explanation:
Given;
mass of the object, m = 2 kg
weigh of the object, W = 20 N
tension on the rope, T = 12 N
The acceleration of the object is calculated by applying Newton's second law of motion as follows;
T = F + W
T = ma + W
ma = T - W
(the negative sign indicates deceleration of the object)
The object accelerates downward at 4 m/s² since the tension on the rope is less than weight of the object.
No. The moon always keeps the same side facing us. Its rotation and revolution periods are equal.
The equivalent gravitational force is ~
We know that ~
where,
= mass of 1st object = 500 kg
= mass of 2nd object = 20kg
- G = gravitational constant =
- r = distance between the objects = 2.12 m
Let's calculate the force ~
Answer:
wavelength decreases and frequency increase
Explanation:
the higher the wavelength the smaller the frequency , the smaller the wavelength the higher the frequency
The question is incomplete.
The distance between the Moon and Earth influences: 1) the attractive gravitational force between them, 2) the tides, 3) the eclipses, 4) the period of each full turn of the moon around the Earth.
Assuming the question refers to the gravitational attraction, we must use the fact that, as per, Newton's Universal Gravitaional Law, the attractive force between the two bodies is inversely related to the square distance that separates them.
Then, if the Moon were twice as far, the gravitational pull would be one fourth (1/4) of actual pull.
