Empirical formula is the simplest ratio of whole numbers of components making up a compound.
empirical formula can be calculated as follows
C H O
mass 12.0 g 2.00 g 5.33 g
number of moles
12.0 g / 12 g/mol 2.00 g / 1 g/mol 5.33 g / 16 g/mol
= 1.00 mol = 2.00 mol = 0.333 mol
divide by the least number of moles
1.00 / 0.333 2.00 / 0.333 0.333/ 0.333
= 3.00 = 6.01 = 1.00
the number of atoms
C - 3
H - 6
O - 1
empirical formula is C₃H₆O
Answer:
Both
Explanation:
Depends on which reaction reffered
Answer:
Option B
Explanation:
The name of the molecule is;
1,1,1,3,3,3-Hexachloropropanone
Now, we can see that it contains propanone which is also called acetone. So it will have a double bond with Carbon(C) and Oxygen (O).
Option B has that double bond between C and O that indicates it propanone or acetone.
Thus, it is the correct option.
Answer:
the protons
Explanation:
the number of protons is constant for each sample of the element. If the number of protons differs, then it is a different element.
