Answer:
those small sediments begin to precipitate, condense on the ground and finally settle.
Explanation:
Sedimentation is a natural process, which occurs spontaneously in nature and promotes the formation of sedimentary rocks.
Answer:
be equal once equilibrium is reached.
Explanation:
Given an equilibrium proton transfer such as the one written below;
HA + :B ⇄ HB + :A
The rate of forward reaction and the rate of reverse reaction becomes equal at equilibrium.
To put it in another way, at equilibrium, the rate of forward and reverse rates of proton transfer will be equal.
Question 17
The subscript 2 is the atomic number for helium and subscript 4 is the mass number for Helium
<u><em>explanation</em></u>
when writing down an isotope of an element the mass number of that isotope is written in upper side of the chemical symbol, while atomic number is written on the lower side.
Since 4 is on upper side it is the mass number of He, while 2 is the atomic number since it is on lower side.
Question 18
The type of radiation emitted when polonium -212 form lead 208 is an alpha particle
<u><em>explanation</em></u>
Alpha decay is a decay in which an atomic nuclei emit an alpha particles and be transformed into different atomic nuclei with a mass number that is reduced by 4
polonium 212 is reduced by 4 to form lead 208 therefore it undergo alpha particle decay.
Answer:
1 mole of molecules = 6.022 × 10²³ molecules
1 = 6.022 × 10²³ molecules / mole
Multiplying a number with [6.022 × 10²³ molecules / mole] is like multiplying the number with 1 so 0.877 mole × 6.022 × 10²³ molecules / mole = 5.28 × 10²³ molecules
5.28 × 10²³ molecules of water is produced.
Explanation:
Answer:
4.74
Explanation:
It is possible to find pH of a buffer (The mixture of a weak acid: Acetic acid, with its conjugate base: Sodium acetate) using Henderson-Hasselbalch equation:
pH = pKa + log₁₀ [A⁻] / [HA]
<em>Where pKa is -log Ka of the weak acid, [A⁻] concentration of the conjugate base and [HA] concentration of the weak acid</em>
pKa of acetic acid is -log 1.8x10⁻⁵ = 4.74
The concentration of both, acetic acid and sodium acetate is 0.1M. Replacing in H-H equation:
pH = pKa + log₁₀ [A⁻] / [HA]
pH = 4.74 + log₁₀ [0.1] / [0.1]
pH = 4.74 + log₁₀ 1
<em>pH = 4.74</em>
Theoretical pH is 4.74
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