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RideAnS [48]
3 years ago
13

Find the area of the trapezoid by decomposing it into other shapes. A) 48 cm2 B) 55 cm2 C) 66 cm2 D) 96 cm2

Mathematics
1 answer:
snow_tiger [21]3 years ago
8 0

Answer:

The answer is B.

Step-by-step explanation:

You have to use area of trapezoid formula, A = 1/2×(a+b)×h where a, b are the side lengths and h is height :

area =  \frac{1}{2}  \times (a + b) \times h

let \: a = 6,b = 16,h = 5

area =  \frac{1}{2}  \times (6 + 16) \times 5

area =  \frac{1}{2}  \times 22 \times 5

area = 11 \times 5

area = 55 \:  {cm}^{2}

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The table represents the function f(x). A 2-column table with 7 rows. The first column is labeled x with entries negative 3, neg
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Answer:

9

Step-by-step explanation:

The table would look like.

x         f(x)

-3       -9

-2       -6

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3 years ago
Consider w=sqrrt2/2(cos(225°) + isin(225°)) and z = 1(cos(60°) + isin(60°)). What is w+ z expressed in rectangular form?
SVETLANKA909090 [29]

Answer:

Option (3)

Step-by-step explanation:

w = \frac{\sqrt{2}}{2}[\text{cos}(225) + i\text{sin}(225)]

Since, cos(225) = cos(180 + 45)

                          = -cos(45) [Since, cos(180 + θ) = -cosθ]

                          = -\frac{\sqrt{2}}{2}

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Therefore, w = \frac{\sqrt{2}}{2}[-\frac{\sqrt{2}}{2}+i(-\frac{\sqrt{2}}{2})]

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z = 1[cos(60) + i(sin(60)]

  = [\frac{1}{2}+i(\frac{\sqrt{3}}{2})

  = \frac{1}{2}(1+i\sqrt{3})

Now (w + z) = -\frac{1}{2}(1+i)+\frac{1}{2}(1+i\sqrt{3})

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                   = \frac{(i\sqrt{3}-i)}{2}

                   = \frac{(\sqrt{3}-1)i}{2}

Therefore, Option (3) will be the correct option.

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