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Andre45 [30]
3 years ago
11

If a garden has an area of 100 square feet how much fencing is needed to enclose the garden

Mathematics
2 answers:
mestny [16]3 years ago
8 0
If 10 x 10 then fencing needed is 4 x 10 =40

if 5 x 20 then fencing needed is 5 x 2 + 20 x 2 = 50

so it depends on its shape, there are several answers if you stick with whole numbers and many more if you use fractions e.g 2.5 x 40
SVEN [57.7K]3 years ago
6 0
Depends on the dimensions of the garden 
the most economical for resources is 10 ft*10 ft=100 sq ft
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What is the y-value of the point of intersection of y=2sinx-cosx and y=cosx over the interval 0≤x≤pi/2 ? a. 0 b. (square root of
horsena [70]
We have that

<span>y=2sinx-cosx
y=cosx
</span>over the interval 0≤x≤pi/2-------> 0≤x≤1.57

using a graph tool
see the attached figure

the solution in the given interval is the point (pi/4, 0.707)
the y-value of the point of intersection is 0.707 -----> √2/2

the answer is the option 
<span>b. (square root of 2)/2</span>

7 0
3 years ago
Read 2 more answers
A cryptographic hash takes a message as input and produces a fixed-length string as output, called the digital fingerprint. A br
Allushta [10]

Answer:

1.85x10^{19} attempts are required to find a matching pair if the digital fingerprint is 64 bits long.

3.40*10^{38} attempts are required to find a matching pair if the digital fingerprint is 128 bits long.

Step-by-step explanation:

Each bit has two options. So

How many attempts are required to find a matching pair if the digital fingerprint is 64 bits long?

So for each of the 64 bits, we have the following number of options.

2 - 2 - 2 - 2 -... - 2

So, in all, there are

T = 2^{64} = 1.85x10^{19}

options.

So, 1.85x10^{19} attempts are required to find a matching pair if the digital fingerprint is 64 bits long.

128 bits long?

Using the same logic as the first question.

T = 2^{128} = 3.40*10^{38}

So, 3.40*10^{38} attempts are required to find a matching pair if the digital fingerprint is 128 bits long.

5 0
3 years ago
What is the correct answer?
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5 0
3 years ago
John is building a fence around his home currently his fence measures 14 feet on each side but he wants to increase only the wid
nalin [4]

Answer:

The dimensions of rectangular fence are 14 feet and 20 feet.

Step-by-step explanation:

We are given the following in the question:

Length of rectangular fence = 14 feet

Width of fence = (14+x) feet

Area of rectangular field = 280 square feet

Area of rectangular field =

A= \text{Length}\times \text{Width}

Putting the values, we get,

280 = 14(14+x)\\\\14 + x = \dfrac{280}{14}\\\\14 + x = 20\\x =20-14\\x = 6

Thus, the dimensions of rectangular fence are 14 feet and 20 feet.

7 0
3 years ago
Can I copy and paste a pic of a problem or diagram ?
ExtremeBDS [4]
No you can not copy and paste a picture of a problem i believe
6 0
3 years ago
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