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SIZIF [17.4K]
3 years ago
14

If Yvonne wanted to make 3 dresses that use 4 7/8 yards of fabric each, how could she estimate to make sure she has enough fabri

c for all of them
Mathematics
1 answer:
Varvara68 [4.7K]3 years ago
3 0
"4 7/8 yards is almost 5 yards. To make certain that you have enough fabric, round up. <span>3 dresses at 5 yard each is 15 yards."</span>
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Each question is worth 10 pts, I will do brainliest for the person who does both and follow pls help.
In-s [12.5K]

Answer:

1. 6

2.

pennies = 9

nickels = 5

quaters = 5

dimes = 10

Step-by-step explanation:

1.

18/3 = 6

as we know that there are 18 scoops, and 3 per icecream, we can divide the two to get the number of ice creams

2.

5n

#n = #q; #q = 2#d, this is a simple ratio, you just plug in the variables to get

5n = 5q = 10d = 15 coins

24 - 15 = 9 pennies

pennies = 9

nickels = 5

quaters = 5

dimes = 10

8 0
2 years ago
Explain the circumstances for which the interquartile range is the preferred measure of dispersion. What is an advantage that th
KatRina [158]

Answer:

Explain the circumstances for which the interquartile range is the preferred measure of dispersion

Interquartile range is preferred when the distribution of data is highly skewed (right or left skewed) and when we have the presence of outliers. Because under these conditions the sample variance and deviation can be biased estimators for the dispersion.

What is an advantage that the standard deviation has over the interquartile​ range?

The most important advantage is that the sample variance and deviation takes in count all the observations in order to calculate the statistic.

Step-by-step explanation:

Previous concepts

The interquartile range is defined as the difference between the upper quartile and the first quartile and is a measure of dispersion for a dataset.

IQR= Q_3 -Q_1

The standard deviation is a measure of dispersion obatined from the sample variance and is given by:

s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

Solution to the problem

Explain the circumstances for which the interquartile range is the preferred measure of dispersion

Interquartile range is preferred when the distribution of data is highly skewed (right or left skewed) and when we have the presence of outliers. Because under these conditions the sample variance and deviation can be biased estimators for the dispersion.

What is an advantage that the standard deviation has over the interquartile​ range?

The most important advantage is that the sample variance and deviation takes in count all the observations in order to calculate the statistic.

8 0
3 years ago
What is the range of the relation below?
Greeley [361]
[6, -infinity)

have a good night
5 0
3 years ago
Evaluate 5+5*5+5/5-5+5*5
rewona [7]

Answer:

51

Step-by-step explanation:

5*5=25

5/5=1

5+25+1-5+25

30+1-5+25

31-5+25

26+25

51

4 0
3 years ago
Read 2 more answers
What is the value of p ?
VLD [36.1K]

Answer:

p = 35

Step-by-step explanation:

180 - 125 = 55

180 - 90 = 90

55 + 90 = 145

180 - 145 = 35

p = 35

6 0
3 years ago
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