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2 years ago

14

If Yvonne wanted to make 3 dresses that use 4 7/8 yards of fabric each, how could she estimate to make sure she has enough fabri

c for all of them

1 answer:

Varvara68 [4.7K]2 years ago

3 0

"4 7/8 yards is almost 5 yards. To make certain that you have enough fabric, round up. <span>3 dresses at 5 yard each is 15 yards."</span>

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The first triangle is larger

Step-by-step explanation:

(1/2)(8)(10)=40

(1/2)(5)(13)=32.5

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2 years ago

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The FBI wants to determine the effectiveness of their 10 Most Wanted list. To do so, they need to find out the fraction of peopl

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<em>98% of confidence intervals for the Population proportion of people who captured after appearing on the 10 most wanted list</em>

(0.3583 , 0.4579)

Step-by-step explanation:

<u>Explanation</u>:-

<em>Given sample size 'n' = 517</em>

Given data Suppose a sample of 517 suspected criminals is drawn. Of these people, 211 were captured.

'x' =211

<em>The sample proportion</em>

$p^{-} = \frac{x}{n} = \frac{211}{517} =0.4081$

$q^{-} = 1-p^{-} = 1- 0.4081 = 0.5919$

<em>98% of confidence intervals for the Population proportion of people who captured after appearing on the 10 most wanted list</em>

$(p^{-} - Z_{\frac{\alpha }{2} } \sqrt{\frac{p^{-} (1-p^{-} )}{n} } , p^{-} + Z_{\frac{\alpha }{2} } \sqrt{\frac{p^{-} (1-p^{-} }{n} } )$

$(0.4081 - 2.326 \sqrt{\frac{0.4081 (0.5919 )}{517} } , 0.4081+ 2.326\sqrt{\frac{0.4081(0.5919 }{517} } )$

(0.4081-0.0498 , 0.4081 +0.0498)

(0.3583 , 0.4579)

<u><em>Conclusion</em></u>:-

<em>98% of confidence intervals for the Population proportion of people who captured after appearing on the 10 most wanted list</em>

(0.3583 , 0.4579)

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3 years ago