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gulaghasi [49]
1 year ago
15

An AC voltage source is connected to a resistor R = 1.90 102 Ω. The output from an AC voltage source is given by the expression

V = (2.20 102 V) sin 2ft. (a) What is the rms voltage across the resistor? V (b) What is the rms current flowing through the resistor? A
Physics
1 answer:
omeli [17]1 year ago
4 0

Answer:

(a) The rms voltage across the resistor is given by V = (2.20 102 V) sin 2ft.

V = (2.20 102 V) sin 2ft

V = (2.20 102 V) (0.707)

V = 1.56 102 V

(b) The rms current flowing through the resistor is given by I = V/R.

I = V/R

I = (1.56 102 V)/(1.90 102 Ω)

I = 8.21 A

<em>Review procedures and confirm results to avoid possible errors.</em>

Explanation:

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10. How do you use a triple-beam balance? Fill in the blanks.
wolverine [178]

Answer:

1st – Place the film canister on the <u>scale</u>.

2nd – Slide the large <u>weight </u>to the right until the arm drops below the line and then move it back one notch.

3rd – Repeat this process with the <u>top</u> weight. When the arm moves below the line, back it up one groove.

4th – Slide the <u>small </u>weight on the front beam until the <u>lines</u> match up.

5th – Add the amounts on each beam to find the total <u>mass </u>to the nearest tenth of a gram.

Explanation:

The triple beam balance is an instrument that is used in measuring the mass of substances to a very high degree of precision. The reading error is given by ±0.05 grams. The triple beam balance as the name implies has three beams that measure substances of different mass levels.

The beams are categorized as small, medium, and large. There is a balance on which the substance to be weighed is placed directly upon. To use this measuring device, the procedures mentioned above are followed.

5 0
3 years ago
A 10 ohms, a 7 ohms and a 14 ohms resistor are connected in series with a 24 V battery. Calculate the equivalent resistance. Ans
Aloiza [94]

Answer:

31ohms

Explanation:

in a series u add all the ohms together

5 0
2 years ago
Which of the following statements is true?
xenn [34]

Correct answer choice is :


C) The freezing and melting temperatures of a substance are the same.


Explanation:


Fluids have a particular temperature at which they convert into solids, identified as their freezing point. In theory, the melting point of a solid should be the same as the freezing point of the liquid. In practice, small variations among these measures can be seen. The freezing point of a matter is the same as that substance's melting point. At this distinct temperature, the substance can exist as either a solid or a liquid. At temperatures below the freezing/ melting point, the substance is a solid.


4 0
3 years ago
Read 2 more answers
A 35.9 g mass is attached to a horizontal spring with a spring constant of 18.4 N/m and released from rest with an amplitude of
lidiya [134]

Answer:

7.74m/s

Explanation:

Mass = 35.9g = 0.0359kg

A = 39.5cm = 0.395m

K = 18.4N/m

At equilibrium position, there's total conservation of energy.

Total energy = kinetic energy + potential energy

Total Energy = K.E + P.E

½KA² = ½mv² + ½kx²

½KA² = ½(mv² + kx²)

KA² = mv² + kx²

Collect like terms

KA² - Kx² = mv²

K(A² - x²) = mv²

V² = k/m (A² - x²)

V = √(K/m (A² - x²) )

note x = ½A

V = √(k/m (A² - (½A)²)

V = √(k/m (A² - A²/4))

Resolve the fraction between A.

V = √(¾. K/m. A² )

V = √(¾ * (18.4/0.0359)*(0.395)²)

V = √(0.75 * 512.53 * 0.156)

V = √(59.966)

V = 7.74m/s

8 0
2 years ago
Read 2 more answers
What do we mean when we say that energy levels are quantized in atoms?
jek_recluse [69]

Answer:

Electrons are located in specific orbit corresponding to discrete energy levels

Explanation:

In Bohr's model of the atom, electron orbit the nucleus in specific levels, each of them corresponding to a specific energy. The electrons cannot be located in the space between two levels: this means that only some values of energy are possible for the electrons, so the energy levels are quantized.

A confirmation of Bohr's model is found in the spectrum of emission of gases. In fact, when an electron jumps from a higher energy level to a lower energy level, it emits a photon whose energy is exactly equal to the difference in energy between the two levels: since the energy levels are discrete, this means that the emitted photons cannot have any value of wavelength, but also their wavelength will appear as a discrete spectrum. This is exactly what it is observed in the spectrum of emission of gases.

3 0
2 years ago
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