All categories

3 years ago

Correct Number Formats Numbers may be entered in several formats - including scientific notation and numerical expressions.

Physics

1 answer:

Illusion [34]3 years ago

6 0

Answer:

a. Valid

b. Invalid

c. Invalid

d. Invalid

e. Valid

f. Valid

g. Invalid

Explanation:

Since, it follows all the four rules,

Therefore, this number is Valid

It uses upper case E, instead of lower case e.

Therefore, it is Invalid

It violates third rule for including unit.

Therefore, it is Invalid

It violates the first rule. As, there is a space between 6 and e. While in the example given in question, there is no gap.

Therefore, it is Invalid

Since, it follows all the four rules,

Therefore, this number is Valid

Since, it follows all the four rules,

Therefore, this number is Valid

It violates third rule for including unit.

Therefore, it is Invalid

You might be interested in

How does time relate to motion

docker41 [41]

As we move, time goes up. Think of it on a graph; as time increases on the x axis, motion can either stay the same, increase, or decrease.

5 0

2 years ago

1. What is the claim made by the Big Bang theory regarding the creation of the universe?

Lena [83]

Answer:

Explanation:

The big bang theory explained that the universe started as a single entity which was created by massive explosion and it create most of the matter i.e galaxies were moving away from the universe in all directions with great speed which then cause massive explosion and bring about cosmos creation.

5 0

3 years ago

Help me solve this please

Leto [7]

Since it's a projectile being launched the only force acting upon it is gravity, since the object is in free fall once it's launched

so to calculate time you'd utilize the general formula of
$xf = xi + vxi(t) + \frac{1}{2} (a) {t}^{2}$
and then solve using time and make it into the y axis, so change the x's to y's, which will change a to g.
since Vyi is always usually 0, you can drop that out of this equation so the formula to find time would be
$t = \sqrt{ \frac{2(y)}{g} }$
So you'll plug in and it'll be
$t = \sqrt{ \frac{2( - 49m)}{ - 9.81 \frac{m}{s {}^{2} } } }$
to find the maximum height you'll have to do some trigonometry to solve it.
To make it easier draw a triangle
put the 60° mark as shown in the picture.
Then you'll need to find the hypotenuse or horizontal to find the vertical
So the hypotenuse would be the 113m/s
so then you'll use
$\ \sin( 60) = ( \frac{o}{h})$

plug in the numbers
$113( \ \sin (60) ) = o$
now that you have the vertical

use the formula
${vf}^{2} = {vi}^{2} + 2gd$
solve for d which will give you the hypotenuse
$d = { (-vertical \frac{m}{s} )}^{2} \div 2( - 9.81 \frac{m}{ {s}^{2} } )$
The "vertical" is what you found in the previous step.
Vf^2 is equal to 0 so you can just drop that number out since it's 0
then once you have that then youre not done yet
since you're on a cliff of 49 m you'll have to add 49m to the previous answer that you found d to find the maximum height.

I hope this helps!

6 0

3 years ago

Use Hooke's Law to determine the work done by the variable force in the spring problem. Nine joules of work is required to stret

natima [27]

Answer:

29.16 J

Explanation:

From Hook's law,

W = 1/2(ke²)..................... Equation 1

Where W = work done, k = Spring constant, e = extension.

Given: W = 9 J, e = 0.5 m.

Substitute into equation 1

9 = 1/2(k×0.5²)

Solve for k

k = 18/0.5²

k = 72 N/m.

The work done required to stretch the spring by additional 0.4 m is

W = 1/2(72)(0.4+0.5)²

W = 36(0.9²)

W = 29.16 J.

6 0

3 years ago

Two identical blocks, A and B, are on a horizontal surface, as shown above. There is negligible friction between the surface and

e-lub [12.9K]

Answer:

the speed of the center of mass stays the same

Explanation:

In a system with no energy loss, momentum is conserved if the mass remains constant. The system described has no change in mass, and energy loss is considered negligible. Hence the product of the total mass and the velocity of its center will be a constant. The center of mass stays the same speed.

6 0

3 years ago