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den301095 [7]
2 years ago
12

What is the mass of a 735-N weight on Earth?

Physics
1 answer:
Allisa [31]2 years ago
3 0
W = mg,      Assuming g ≈ 9.8 m/s² on the earth surface.

735 N =  m* 9.8

735/9.8 =  m

75 = m

Mass , m = 75 kg.  B.
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A toy rocket moving vertically upward passes by a 2.0-m-high window whose sill is 8.0 m above the ground. The rocket takes 0.15
sveta [45]

Answer:

v_i = 18.86 m/s

Explanation:

As we know that the speed of the rocket is v1 and v2 at the bottom and top of the window

then we will have

d = (\frac{v_1 + v_2}{2}) t

2 = (\frac{v_1 + v_2}{2})(0.15)

26.67 m/s = v_1 + v_2

also we know that

v_2 - v_1 = (-9.81)(t)

v_2 - v_1 = (-9.81)(0.15) = -1.47

now we have

v_2 = 12.6

also we have

v_1 = 14.1 m/s

now if the sill of the window is at height 8 m from the ground then we have

v_1^2 - v_i^2 = 2 a h

(14.1^2) - v_i^2 = 2(-9.81)(8)

v_i = 18.86 m/s

8 0
3 years ago
The average intensity of light emerging from a polarizing sheet is 0.708 W/m2, and that of the horizontally polarized light inci
Pachacha [2.7K]

Answer:

Angle θ = 30.82°

Explanation:

From Malus’s law, since the intensity of a wave is proportional to its amplitude squared, the intensity I of the transmitted wave is related to the incident wave by; I = I_o cos²θ

where;

I_o is the intensity of the polarized wave before passing through the filter.

In this question,

I is 0.708 W/m²

While I_o is 0.960 W/m²

Thus, plugging in these values into the equation, we have;

0.708 W/m² = 0.960 W/m² •cos²θ

Thus, cos²θ = 0.708 W/m²/0.960 W/m²

cos²θ = 0.7375

Cos θ = √0.7375

Cos θ = 0.8588

θ = Cos^(-1)0.8588

θ = 30.82°

4 0
3 years ago
2. An electron and a proton are separated by 5 cm:
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Answer:

a) the charge of an electron is equivalent to the magnitude of the elementary charge but barring a negative sign since the side of the elementary charge is roughly 1.602 * 10 - 19 Columbus then the charge of the electronic is-1.602 * 10 - 19

b) b=2T on the electron moving in the magnetic field

7 0
2 years ago
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Helen [10]

Answer:

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2 years ago
Read 2 more answers
A physics instructor wants to project a spectrum of visible-light colors from 400 nm to 700 nm as part of a classroom demonstrat
Likurg_2 [28]

Answer:

  Dr = 263 10⁻⁶ m

Explanation:

The diffraction pattern for constructive interference is described by

        a sin θ = m λ

in this it indicates that the order of diffraction is m = 1

Let's use a direct proportion rule to find the separation of two slits. If there are 600 lines in 1 me, what is the distance between 2 slits

   a = 2 lines 1/600

   a = 2/600

    a = 3.33 10⁻³ mm = 3.33 10⁻⁴ cm

let's use trigonometry

      tan θ = y / L

as the measured angles are small

      tan θ = sin θ / cos θ sin θ

      sin θ = y / L

we substitute

     a  y/L = λ

     y = λ L / a

for λ = 400 10-9 m

      I = 400 10⁻⁹ 2.9 / 3.33 10⁻³

      i = 346.89 10⁻⁶ m

f

or λ = 700 nm

        y_f = 700 10⁻⁻⁹ 2.9 / 3.33 10⁻³

        y_f = 609.609 10⁻⁶ m

the separation of this spectrum

        Δr = v_f - i

        Dr = (609.609 - 346)  10 ⁻⁶

        Dr = 263 10⁻⁶ m

4 0
3 years ago
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