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Lena [83]
3 years ago
12

Place the ball in the plastic bag, and twist the top so the ball is secure in the bag. Wrap the twisted portion with tape so it

stays tight. Use the hole punch or scissors to poke a hole in the part of the bag that’s above the ball. Slip an end of the string through the hole, and tie a knot. This is your pendulum. Hold the loose end of the string still with one hand. With the other hand, raise the ball in an arc so that it’s almost level with the hand holding the string. With the string taut, let the ball go. What do you observe?
Physics
1 answer:
Irina18 [472]3 years ago
8 0

I observe two phenomena:

Obs-1:  I don't have the materials here to perform this experiment.

Obs-2:  You have not done the assigned experiment, and you apparently have no intention of doing it.

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A 2.5 m -long wire carries a current of 8.0 A and is immersed within a uniform magnetic field B⃗ . When this wire lies along the
leva [86]

Answer:

Explanation:

Let the magnetic field be B = B₁i + B₂j + B₃k

Force = I ( L x B )  , I is current , L is length and B is magnetic field .

In the first case

force = - 2.3 j N

L = 2.5 i

puting the values in the equation above

- 2.3 j = 8 [ 2.5 i x ( B₁i + B₂j + B₃k )]

= - 20 B₃ j + 20 B₂ k

comparing LHS and RHS ,

20B₃ = 2.3

B₃ = .115

B₂ = 0

In the second case

L = 2.5 j

Force = I ( L x B )

2.3i−5.6k = 8 ( 2.5 j x (B₁i + B₂j + B₃k )

=  - 20 B₁ k + 20B₃ i

2.3i−5.6k = - 20 B₁ k + 20B₃ i

B₃ = .115

B₁ = .28

So magnetic field B = .28 i + .115 B₃

Part A

x component of B = .28 T

Part B

y component of B = 0

Part C

z component of B = .115 T .

8 0
3 years ago
Please help me on this
QveST [7]

Answer:

i think its bulb 2

Explanation:

4 0
2 years ago
If μs is greater than some critical value, the woman cannot start the crate moving no matter how hard she pushes. calculate this
fiasKO [112]

weight = mg acts downwards <span>
normal force = N acts upwards. 
and force F acts at an angle θ below the horizontal. 
(Let us assume that the woman pushes from the left, so F is acted towards the right, which is below the horizontal) 
so that, Frictional force, f=us*N acts towards the left 

Now we balance the forces along x and y directions: 
y direction: N = mg + F sinΘ 
x direction: us * N = F cosΘ 

We let the value of µs be equal to a value such that any F will not be able to move the crate. Then, if we increase F by an amount F', then the force pushing the crate towards the right also increases by F' cosΘ. Additionally, the frictional force f must raise by exactly this amount. 
Since f can’t exceed us*N, so the normal force must increase by F' cosΘ/us. 
Also, from the y direction equation, the normal force exceeds by F' sin Θ. 

<span>These two values must be the same, therefore:
<span>us = cot θ</span></span></span>

4 0
2 years ago
In an electric header 500w is written. What is its meaning​
Fiesta28 [93]

Answer:

Because it's wattage is 500W.

Explanation:

This is its mearurement

4 0
2 years ago
You attach a 2.90 kg mass to a horizontal spring that is fixed at one end. You pull the mass until the spring is stretched by 0.
Murljashka [212]

Answer:

Explanation:

The spring is stretched by .5 m and then released that means its amplitude of oscillation A is 0.5 m .

A = 0.5 m

After the release at one extreme point , the mass comes to rest again at another extreme point after half the time period ie

T / 2 = .3 s

T = 0.6 s

Angular velocity

ω = \frac{2\times \pi}{T}

ω = \frac{2\times \pi}{0.6}

ω = 10.45

Maximum velocity  = ω A

ω and  A are angular velocity and amplitude of oscillation.

Maximum velocity  = 10.45 x .5

= 5.23 m /s

7 0
3 years ago
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