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antiseptic1488 [7]
3 years ago
5

________ cable is NOT subject to electromagnetic interference or radio frequency interference. Polycarbonate Twisted-pair Coaxia

l Fiber-optic
Physics
1 answer:
malfutka [58]3 years ago
5 0

Answer:

The correct option is: d. Fiber-optic

Explanation:

A fiber-optic cables or an optical-fiber cable is a cable that is composed of a bundle of optical fibers. These cables are used for transmitting information or digital signals over long distances.

Each optical fiber in an optical-fiber cable is individually coated with a protective plastic cover and contained in a protective tube. Therefore, an optical-fiber cable is not affected by any electromagnetic interference or radio frequency interference.

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41. City A lies 30 km directly south of city B. A bus, beginning at city A travels 50 km at 37° north of east to reach city C. H
Nana76 [90]

Answer:

B) 40 km West

Explanation:

Let position of B is origin so with respect of City B the position of A is given as

r_A = 30 km south of city B

now Bus starts from City A and travels a distance of 50 km at 37 degree North of East to reach city C

so it is

r_{CA} = 50(cos37\hat i + sin37 \hat j)

r_{CA} = 40\hat i + 30\hat j

now the position of C is given with respect to A

in order to find the position of C with respect to B we can say

r_C = r_{CA} + r_A

r_C = 40\hat i + 30\hat j + (-30 \hat j)

r_C = 40 \hat i

so in order to reach at city B from city C bus has to travel 40 km towards West

7 0
3 years ago
How much work does it take to lift an object weighing 200N to a distance of 20 meters
Bogdan [553]

Answer:

4000 J

Explanation:

W = F = 2000N , s = 20 m

Workdone = F × s = 200 × 20 = 4000J

7 0
3 years ago
Read 2 more answers
A simple series circuit consists of a 150 Ω resistor, a 29 V battery, a switch, and a 2.1 pF parallel-plate capacitor (initially
Rufina [12.5K]
Find the electric flux and the disp at t=0.50ns 
<span>Given: </span>
<span>Resistor R = 160 Ω </span>
<span>Voltage ε = 22.0 V </span>
<span>Capacitor C = 3.10 pF = 3.10 * 10^-12 F </span>
<span>time t = 0.5 ns = 0.5 * 10^-9 s </span>
<span>ε0 = 8.85 * 10^-12 </span>
<span>Solution: </span>
<span>ELECTRIC FLUX: </span>
<span>Φ = Q/ε0 </span>
<span>we have ε0, we need to find Q the charge </span>
<span>STEP 1: FIND Q </span>
<span>Q = C ε ( 1 - e^(-t/RC) ) </span>
<span>Q = { 3.10 * 10^-12 } { 22.0 } { 1 - e^(- 0.5 * 10^-9 / 160 *3.10 * 10^-12 ) } </span>
<span>Q = { 3.10 * 10^-12 } { 22.0 } { 1 - 0.365 } </span>
<span>Q = { 3.10 * 10^-12 } { 22.0 } { 0.635 } </span>
<span>Q = 43.31 * 10^-12 C </span>
<span>STEP 2: WE HAVE Q AND ε0 > >>> SOLVE FOR ELECTRIC FLUX >>> </span>
<span>Φ = Q/ε0 </span>
<span>Φ = { 43.31 * 10^-12 C } / { ε0 = 8.85 * 10^-12 } </span>
<span>Φ = 4.8937 = 4.9 V.m </span>
<span>DISPLACEMENT CURRENT </span>
<span>we use the following equation: </span>
<span>I = { ε / R } { e^(-t/RC) } </span>
<span>I = { 22 / 160 } { e^(- 0.5 * 10^-9 / 160 *3.10 * 10^-12 ) } </span>
<span>I = { 0.1375 } { 0.365 } </span>
<span>I = 0.0502 A = 0.05 A </span>
8 0
4 years ago
A wheel is rotating freely at angular speed 530 rev/min on a shaft whose rotational inertia is negligible. A second wheel, initi
Grace [21]

Answer: 53\ rev/min

Explanation:

Given

angular speed of wheel is \omega_1 =530\ rev/min

Another wheel of 9 times the rotational inertia is coupled with initial wheel

Suppose the initial wheel has moment of inertia as I

Coupled disc has 9I as rotational inertia

Conserving angular momentum,

\Rightarrow I\omega_1=(I+9I)\omega_2\\\\\Rightarrow \omega_2=\dfrac{I}{10I}\times 530\\\\\Rightarrow \omega_2=53\ rev/min

5 0
3 years ago
For the vectors shown in the figure, determine<br> (Figure 1) the magnitude of B−3A.
Vera_Pavlovna [14]

Answer:

idk dude

Explanation:

just ask ur teacher

5 0
4 years ago
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