Answer: I didn't see a difference because the large ball's vertical displacement and velocity are the same as the small one's.
Explanation:
Answer:
there will be collision
Explanation:
= speed of sue = 34 m/s
= speed of van = 5.20 m/s
= speed of sue relative to van = 
= 34 - 5.20 = 28.8 m/s
= stopping distance after brakes are applied
= distance between sue and van = 160 m
= final speed of sue = 0 m/s
= acceleration = - 1.80 m/s²
Using the kinematics equation
m
Since 
hence there will be collision
The force equation can easily prove this. F=ma. This states that the force on an object is equal to mass times acceleration. If the mass stays the same and the velocity of the cars increases than that means there is a larger force. This is because in both cases the cars are stopping in almost an instant and the times of the crashes are theoretically identical. Acceleration is the change in velocity over time. If the velocity is higher with the same amount of time than that means there is a higher acceleration. If you plug a higher acceleration into the force equation then you wind up with a higher force and in turn a more damaging collision.
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Do they give answer choices? or is it free write? i’ll help if you tell me!!
Answer:
the knee extensors must exert 15.87 N
Explanation:
Given the data in the question;
mass m = 4.5 kg
radius of gyration k = 23 cm = 0.23 m
angle ∅ = 30°
∝ = 1 rad/s²
distance of 3 cm from the axis of rotation at the knee r = 3 cm = 0.03 m
using the expression;
ζ = I∝
ζ = mk²∝
we substitute
ζ = 4.5 × (0.23)² × 1
ζ = 0.23805 N-m
so
from; ζ = rFsin∅
F = ζ / rsin∅
we substitute
F = 0.23805 / (0.03 × sin( 30 ° )
F = 0.23805 / (0.03 × 0.5)
F F = 0.23805 / 0.015
F = 15.87 N
Therefore, the knee extensors must exert 15.87 N
