All categories

3 years ago

Which describes a reflected image in a plane mirror?

Physics

1 answer:

Paul [167]3 years ago

4 0

Answer:

B. The image is right-left reversed and about as far away from the mirror as the reflected object.

Explanation:

A plane mirror is used in several ways in our life, from the mirror that we have on the bathroom to the mirrors we use on cars, the main difference is that the mirror reflects the image reversed on the Vertical axis, which means that the left is the right and the right is the left, a mirror also protrays objects at a certain distance, about as far away from the mirror as the reflected object but they are actually closer in real life.

You might be interested in

Bruh how did i get 3 warnings and 3 brainliests removed

Brums [2.3K]

Answer:

Wait, that can happen? I'm sorry.

Explanation:

5 0

3 years ago

Read 2 more answers

What are some ways to conserve electricity

emmasim [6.3K]

Turn off lights when leaving rooms.

Unplug unused appliances. Even when powered off these appliances use electricity.

Replace regular light bulbs with energy saving bulbs.

7 0

3 years ago

Read 2 more answers

A shopper does 157 J of work pushing a cart with 10.9 N force

Tanzania [10]

The cart travelled a distance of 14.4 m

Explanation:

The work done by a force when pushing an object is given by:

$W=Fd cos \theta$

where:

F is the magnitude of the force

d is the displacement

$\theta$ is the angle between the direction of the force and the displacement

In this problem we have:

W = 157 J is the work done on the cart

F = 10.9 N is the magnitude of the force

$\theta=0^{\circ}$ , assuming the force is applied parallel to the motion of the cart

Therefore we can solve for d to find the distance travelled by the cart:

$d=\frac{W}{F cos \theta}=\frac{157}{(10.9)(cos 0)}=14.4 m$

Learn more about work:

brainly.com/question/6763771

brainly.com/question/6443626

#LearnwithBrainly

4 0

3 years ago

The half-life of plutonium 239 is 24,200 years. Assume that the decay rate is proportional to the amount. Determine the amount o

kotykmax [81]

Answer:

time taken is equal to 14,156 years

Explanation:

we know,

$Y=Ae^{-kt}$

at t = 0

Y(0) = A

given that half life of plutonium 239 = 24,200

$\dfrac{A}{2}=Ae^{-kt}\\0.5=e^{-kt}\\k\times 24200 = ln(2)\\k = \dfrac{ ln(2)}{24200}$

$Y=Ae^{-kt}$

$\frac{3}{2} = e^{-kt}\\ln(1.5)=-\dfrac{ ln(2)}{24200}\times t\\t=-\dfrac{ln(1.5)\times 24200}{ ln(2)}\\t=14,156 \ years$

hence time taken is equal to 14,156 years

5 0

3 years ago

The motion of a particle is defined by the relation x 5 t 3 2 9t 2 1 24t 2 8, where x and t are expressed in inches and seconds,

shutvik [7]

Answer:

a) t = 2.0 s, b) x_f = - 24.56 m, Δx = 16.56 m

Explanation:

This is an exercise in kinematics, the relationship of position and time is indicated

x = 5 t³ - 9t² -24 t - 8

a) ask when the velocity is zero

speed is defined by

v = $\frac{dx}{dt}$

let's perform the derivative

v = 15 t² - 18t - 24

0 = 15 t² - 18t - 24

let's solve the quadratic equation

$t = \frac{18 \pm \sqrt{18^2 + 4 \ 15 \ 24} }{2 \ 15}$

t = $\frac{18 \pm 42}{30}$

t1 = -0.8 s

t2 = 2.0 s

the time has to be positive therefore the correct answer is t = 2.0 s

b) the position and distance traveled for a = 0

acceleration is defined by

a = dv / dt

a = 30 t - 18

a = 0

30 t = 18

t = 18/30

t = 0.6 s

we substitute this time in the expression of the position

x = 5 0.6³ - 9 0.6² - 24 0.6 - 8

x = 1.08 - 3.24 - 14.4 - 8

x = -24.56 m

we see that all the movement is in one dimension so the distance traveled is the change in position between t = 0 and t = 0.6 s

the position for t = 0

x₀ = -8 m

the position for t = 0.6 s

x_f = - 24.56 m

the distance

ΔX = x_f - x₀

Δx = | -24.56 -(-8) |

Δx = 16.56 m

5 0

3 years ago