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1 year ago

7

A machine has a mechanical advantage of 0.6. what force should be applied to the machine to make it apply 600 n to an object? 10

0 n 360 n 1000 n 3600 n

1 answer:

Akimi4 [234]1 year ago

6 0

Answer:

frictional force, should be applied to the machine

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A 60.0 kg ballet dancer stands on her toes during a performance with four square inches (26.0 cm2) in contact with the floor. Wh

Anit [1.1K]

Answer:

Explanation:

Given

Mass of dancer $m=60\ kg$

Area of contact $A=26\ cm^2$

(a)If dancer is stationary

Pressure exerted by Floor is given by load per unit area of contact

$P=\frac{weight}{A}$

$P=\frac{mg}{A}$

$P=\frac{60\times 9.8}{26\times 10^{-4}}$

$P=226.153 kN$

(b)If dancer is leaping upwards with an acceleration of $a=5 m/s^2$

So apparent weight of dancer is $W'=mg+ma$

$W'=m(g+a)=60\cdot (9.8+5)$

$W'=888\ N$

$Pressure=\frac{W'}{A}$

$Pressure=\frac{888}{26\times 10^{-4}}$

$=341.53\ kN$

5 0

3 years ago

Asteroid Ida was photographed by the Galileo spacecraft in 1993, and the photograph revealed that the asteroid has a small moon,

Nady [450]

Answer:

The orbital speed of Dactyl is $5.55m/s$

Explanation:

The orbital speed can be determined by the combination of the universal law of gravity and Newton's second law:

$F = G\frac{M \cdot m}{r^{2}}$ (1)

Where G is gravitational constant, M is the mass of the asteroid, m is the mass of the moon and r is the distance between them

In the other hand, Newton's second law can be defined as:

$F = ma$ (2)

Where m is the mass and a is the acceleration

Then, equation 2 can be replaced in equation 1

$m\cdot a = G\frac{M \cdot m}{r^{2}}$ (2)

However, a will be the centripetal acceleration since the moon Dactyl describe a circular motion around the asteroid

$a = \frac{v^{2}}{r}$ (3)

$m\frac{v^{2}}{r} = G\frac{M \cdot m}{r^{2}}$ (4)

Therefore, v can be isolated from equation 4:

$m \cdot v^{2} = G \frac{M \cdot m}{r^{2}}r$

$m \cdot v^{2} = G \frac{M \cdot m}{r}$

$v^{2} = G \frac{M \cdot m}{rm}$

$v^{2} = G \frac{M}{r}$

$v = \sqrt{\frac{G M}{r}}$ (5)

Finally, the orbital speed can be found from equation 5:

Notice, that it is necessary to express r in units of meters.

$r = 95km \cdot \frac{1000m}{1km}$ ⇒ $95000m$

$v = \sqrt{\frac{(6.672x10^{-11}N.m^{2}/kg^{2})(4.4x10^{16}kg)}{95000m}}$

$v = 5.55m/s$

Hence, the orbital speed of Dactyl is $5.55m/s$

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2 years ago

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kifflom [539]

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3 years ago

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The state of matter that has particles in a fixed position, with a definte volume and shape is

Rainbow [258]

That's the description of the SOLID phase of matter.

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3 years ago

What is the percentage of the incoming solar radiation from the top of the atmosphere the gets reflected right back out into spa

san4es73 [151]

Answer: We can define the solar constant as a measure of the luminous flux density.

Explanation:

The solar constant or solar constant is the amount of energy radiated at the upper limit of the Earth's atmosphere per unit time perpendicular to the unit surface, at the Earth's mean distance from the sun. Amounts to 1367.7 W / m² ± 6 W / m². The sun's constant includes all kinds of electromagnetic radiation, not just visible light. The average value is 1,368 kW / m2 and changes slightly with solar cycles. The amount of these constant changes over one year and has different benefits.

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3 years ago