A machine has a mechanical advantage of 0.6. what force should be applied to the machine to make it apply 600 n to an object? 10
1 answer:
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Answer:
x = 0.75801 = 75.801%
T_2 = 72..78 degree F
Explanation:
From superheated R 134 a properties table
At 200 lb/in^2 and 200 degree F
steady flow energy equation is givena s
At 90 lb/in2 Tsat = 72.78 degree F
hfg = 77.345 Btu/lbm
h = hf + x hfg
solving for x we get
x = 0.75801 = 75.801%
Answer:
Explanation:
Given
mass m collides elastically with floor and jump to its original height I .e.velocity of rebound is same as the initial velocity
Impulse imparted by steel ball to the ground is given by the change in momentum of steel ball
and impulse is product of average force and time
so we need time to calculate the average force. So, option e is correct