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1 year ago

7

A machine has a mechanical advantage of 0.6. what force should be applied to the machine to make it apply 600 n to an object? 10

0 n 360 n 1000 n 3600 n

1 answer:

Akimi4 [234]1 year ago

6 0

Answer:

frictional force, should be applied to the machine

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On a certain map, every 3 cm represents 6 km on earth surface. Which ratio represents the scale of the map, which shows how the

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Answer:

1 : 2 cm/km or $\frac{1}{2} \, \frac{cm}{km}$

One cm represents 2 km.

Explanation:

If 3 cm represents 6 km on the earth, the ratio to consider is: 3 : 6 cm/km which is the same as:

1 : 2 cm/km or $\frac{1}{2} \, \frac{cm}{km}$

One cm represents 2 km.

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3 years ago

Name 7 characteristics that are unique to mammals.

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3 years ago

Read 2 more answers

A barbel weighing 215N is raised to a height of 2.0 M above the ground. It is then dropped from that height.

aleksandrvk [35]

Answer:

430 J
6.26 m/s

Explanation:

A. The kinetic energy is the same as the initial potential energy:

PE = mgh = (215 N)(2.0 M) = 430 J

__

B. The velocity achieved by falling from a height h is given by ...

v = √(2gh)

v = √(2·9.8 m/s^2·2 m) = √(39.2 m^2/s^2)

v ≈ 6.26 m/s

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3 years ago

A computational model predicts the maximum potential energy a roller coaster car can have given its mass and its speed at the lo

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Answer:

The prediction for its maximum potential energy is 109,375 J

Explanation:

Given;

mass of the coaster car, m = 350 kg

speed of the coaster car at the lowest point, v = 25 m/s

The coaster car will have maximum kinetic energy at the lowest point and based on law of conservation of mechanical energy, the maximum kinetic energy of the coaster car at the lowest point will be equal to maximum potential energy at the highest point.

$K.E_{max} = P.E_{max}$

$K.E_{max} = \frac{1}{2} mv^2\\\\K.E_{max} = \frac{1}{2} (350)(25)^2\\\\K.E_{max} =109,375 \ J$

$Thus, P.E_{max} = 109,375 \ J$

Therefore, the prediction for its maximum potential energy is 109,375 J

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2 years ago