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Afina-wow [57]
4 years ago
6

Two charges, -20 C and +4.7 C, are fixed in place and separated by 3.0 m. a. At what spot along a line through the charges is th

e net electric field zero? Give the distance of the spot to the positive charge in meters (m). (Hint: The spot does not necessarily lie between the two charges.) b. What would be the force on a charge of +14 C placed at this spot?

Physics
1 answer:
Pani-rosa [81]4 years ago
6 0

The zero net electric field point is at a point that is 0.98 m away from 4.7C charge.If a 14C charge is placed at this point then, force acted on the charge placed at this point is equal to zero.

Explanation:

Let at A both net electric field is zero then

At A ,E1=E2

E1=k*Iq1I / (d+x)^2

E2=k*Iq2I /x^2

Equating both

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Answer:

V = (5.8cm/s)i, (4.7cm/s)j

Explanation:

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To obtain the average velocity (V)

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To obtain r1 and r2, substitute t1 = 0 and t2 = 2 respectively in the equation above

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r1 = 4.50 cm + 0 + 0 = (4.50cm)i + 0j

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