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anzhelika [568]
3 years ago
15

Charged objects have a _________ charge. A. net B. moving C. positive D. negative

Physics
1 answer:
lidiya [134]3 years ago
6 0
Charged objects have a Net charge.
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Which describes the motion in a convection current? horizontal motion only vertical motion only linear motion circular motion
Orlov [11]

Answer:

circular motion

Explanation:

Circular motion can be regarded as

movement of particular object along the circumference in a circle. It is

rotation of particular object along a circular path. Circular motion could be

uniform, along with constant angular rate of rotation as well as constant speed. It could also be non-uniform along with changing rate of rotation. The acceleration that is been experienced when one is in uniform circular motion is called"Centripetal acceleration"

Convection currents is type of current that takes place after a reservoir of fluid has been heated at the bottom, then cool at the top.the fluid expand as a result of Heat , then density decreases, the plates on top of them is been carried as a result of circular motion of the convection

8 0
3 years ago
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Water flows past a flat plate that is oriented parallel to the flow with an upstream velocity of 0.4 m/s. (a) Determine the appr
Trava [24]

Answer:

1.12 m

0.08291 m

Explanation:

u = Upstream velocity = 0.4 m/s

Re = Reynold's number = 5\times 10^5 (turbulent)

\nu = Viscosity of water = 1.12\times 10^{-6}\ Pas

Here the flow is turbulent so we have the relation

Re_{xcr}=\frac{ux_{cr}}{\nu}\\\Rightarrow x_{cr}=\frac{Re_{xcr}\nu}{u}\\\Rightarrow x_{cr}=\frac{5\times 10^5\times 1.12\times 10^{-6}}{0.4}\\\Rightarrow x_{cr}=1.4\ m

The approximate location downstream from the leading edge where the boundary layer becomes turbulent is 1.4 m

Boundary layer thickness relation is given by

\delta={\frac{\nu x}{u}}^{\frac{1}{5}}\\\Rightarrow \delta={\frac{1.12\times 10^{-6}\times 1.4}{0.4}}^{\frac{1}{5}}\\\Rightarrow \delta=0.08291\ m

The boundary layer thickness is 0.08291 m

4 0
4 years ago
What kind of engine do most cars use today
Nadusha1986 [10]

Answer:

4 stroke 4 cylinder Natural Aspirated Gasoline engine

Explanation:

im not 100%  sure

4 0
3 years ago
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What types of substances tend to be acidic
Fynjy0 [20]
Generally speaking, there are two types of substances; acids and bases. Bases tend to be alkaline and have a higher Ph while acids are acidic and have a lower value on the Ph scale. 
3 0
3 years ago
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A 25 kg circular disk has a diameter of 2.5 feet and a thickness of 2.5 cm. Find the density of the disk in kg/m3. Next, find th
Gre4nikov [31]

Answer:

Assume that \rm g= 9.81\; N\cdot kg^{-1}; \rho(\text{Water}) = \rm 1000\;kg\cdot m^{-3}.

Density of the disk: approximately \rm 2.19\times 10^{3}\; kg\cdot m^{-3}.

Weight of the disk: approximately \rm 245\;N.

Buoyant force on the disk if it is submerged under water: approximately \rm 112\; N.

The disk will sink when placed in water.

Explanation:

Convert the dimensions of this disk to SI units:

  • Diameter: d = \rm 25\; inches = (25\times 0.3048)\; m = 0.762\;m.
  • Thickness h = \rm 2.5\; cm = (2.5\times 0.01)\; m = 0.025\;m.

The radius of a circle is 1/2 its diameter:

\displaystyle r = \rm \frac{1}{2}\times 0.762\;m = 0.381\; m.

Volume of this disk:

V(\text{disk}) = \pi\cdot r^{2}\cdot h = \pi\times 0.381^{2}\times 0.025 \approx 0.0114009\; m^{3}.

Density of this disk:

\displaystyle \rho(\text{disk}) = \frac{m}{V} = \rm \frac{25\; kg}{0.0114009\; m^{3}} = 2.19\times 10^{3}\;kg\cdot m^{-3}.

\rho(\text{disk}) >\rho(\text{water}) indicates that the disk will sink when placed in water.

Weight of the object:

W(\text{disk}) = m\cdot g = \rm 25\times 9.81 = 245.25\; N.

The buoyant force on an object in water is equal to the weight of water that this object displaces. When this disk is submerged under water, it will displace approximately \rm 0.0114009\; m^{3} of water. The buoyant force on the disk will be:

\begin{aligned}F(\text{buoyant force}) &= W(\text{Water Displaced}) \\& = \rho\cdot V(\text{Water Displaced})\cdot g\\ & = \rm 1\times 10^{3}\; kg\cdot m^{-3}\times 0.0114009\; m^{3}\times 9.81\; N\cdot kg^{-1}\\ &\approx \rm 112\; N\end{aligned}.

The size of this disk's weight is greater than the size of the buoyant force on it when submerged under water. As a result, the disk will sink when placed in water.

3 0
3 years ago
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