Answer:
in 6.0 E3 g of blood at a concentration of 0.62 ppm there are 3.5g of lead content
Explanation:
- blood density: 1.06 g/L
- ppm ≡ mg Pb / L blood
⇒ V blood = 6.0E3gblood * L / 1.06gblood = 5660.37 L blood
<u> mass of lead:</u>
⇒ 5660.37 L blood * 0.62 mg Pb / L blood * 0.001 g / mg
⇒ mass = 3.509 g of lead
Solution :
In the process to isolate gold that has a 80 percent yield, a 3.00 g of Au is being isolated.
That is, the actual yield of Au is 3. 00 g
Therefore, we need to find the theoretical yield.
As we know,


As actual yield = 3.00 g
percent yield = 80 %
So, theoretical yield = 
= 3.75 g
Thus he should be able to get 3.75 g which is the theoretical yield of Au.
Ionic compound
Al +3 charge, Aluminum
S -2 charge, Sulfur
Al2S3
Im pretty sure its Taxes?