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vaieri [72.5K]
3 years ago
6

How many liters of solution will contain 1.5 moles of CaCl2 if the solution is 6.0 M CaCl2?

Chemistry
1 answer:
sashaice [31]3 years ago
6 0

Answer:

0.25

Explanation:

volume= number of moles over concentration

hence v=1.5/6

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The backbone in a nucleic acids strand is called:
Nina [5.8K]

Answer: Option (c) is the correct answer.

Explanation:

Backbone in a nucleic acids strand is made up of sugar molecules attached with phosphodiester bond.

This sugar-phosphate linkage helps in joining of nucleotides in a DNA sequence. Due to this backbone structural framework of nucleotides is formed. In DNA, the sugar is deoxyribose.  

Thus, we can conclude that the backbone in a nucleic acids strand is called sugar backbone.

4 0
3 years ago
Which physical property can be used to classify oxygen, helium, propane, and hydrogen as being similar?
PSYCHO15rus [73]

Answer:

state of matter

Explanation:

Because there are three state of matter namely:liquid,solid and gas and oxygen is a gas.

4 0
3 years ago
A sample of an unknown gas at STP has a density of 0.630 gram per liter. What is the gram molecular mass of this gas?
jeyben [28]
<span>STP means standard temperature and pressure at 0°C (273K) and 1 atm (atmosphere). The density of the unknown gas is 0.63 gram per liter. The deal gas equation is PV = nRT. The n is the numer of moles and can be represented as mass of the gas, m, divided by the molar mass, c.  so we have,</span>  

PV = nRT
PV = (m/c)RT
Since the density is d = m/V
Pc = (m/V)RT
Pc = dRT
c = drT/P  

substitute the values into the equation,
c = [(0.63g/L)(0.08206 L-atm/mol-K)(273K)]/(1atm)
<u>c = 14.11 g/mol</u>
3 0
3 years ago
A gas occupies 2.0 m3 at 100.0k and exerts a pressure of 100.0kPa. What volume will the gas occupy if the temperature is increas
Svetradugi [14.3K]
According to ideal gas equation, we know for 1 mole of gas: PV=RT
where P = pressure,  T = temperature, R = gas constant, V= volume
If '1' and '2' indicates initial and final experimental conditions, we have
\frac{P1V1}{P2V2} =  \frac{T1}{T2}

Given that: V1 = 100.0 kPa, T1 = 100.0 K, V1 = 2.0 m3, T2 = 400 K, P2 = 200.0 kPa

∴ on rearranging above eq., we get V2 = \frac{P1V1T2}{T1} =  \frac{100 X 2 X 400}{200X100}
∴ V2 = 4 m3 
7 0
3 years ago
Answer me fast!
Ede4ka [16]
Distance and time is needed for determining speed
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