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Eduardwww [97]
3 years ago
9

an NFL team kicker misses 2 out of every 11 field goals if he missed 8 filed goals throughout the season how many did he attempt

Mathematics
2 answers:
klasskru [66]3 years ago
7 0

Answer:

He attempted 88 and made 44 of his attempts

Step-by-step explanation:


Aleks [24]3 years ago
3 0
For this equation, you want to do it in fractions/ratios to properly solve it. You would have his average misses out of every field goal and his real missed attempts over total. It would look like this

\frac{2}{11}  =   \frac{8}{x}

You want to solve for x since x is the total amount of field goals that he attempted. You can do this by doing cross multiplication:

(2)(x) = (8)(11)

From here you can get:

2x = 88

Divide each side by 2 to isolate x and you get:

x=  44

So he made a total of 44 field goals.
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Your answer is B. 3/4

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1/2 of a number is 32 what's the answer
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64 !! because 32 x 2 is 64
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3 years ago
10. (a) Consider the following matrices: A = ( 2 ) B = (3) and C = (-3) w = Find the det(A). [1] (ii) Is the matrix A singular?
Viefleur [7K]

i) We have to find the determinant of A.

We can do this as:

\det(A)=|\begin{bmatrix}{3} & {6} \\ {1} & {-2}\end{bmatrix}|=3*(-2)-6*1=-6-6=-12

ii) We have to find if the matrix A is singular.

Singular matrix have determinant equal to 0.

This is not the case for A, as its determinant is -12. Then, A is not a singular matrix.

iii) We have to find the values of x and y so that AB = C.

We have to write the matrix multiplication and we will obtain a system of linear equations:

We can now solve the system of equations by adding 3 times the second equation to the first equation:

\begin{gathered} 3(x-2y)+(3x+6y)=3(-3)+(-3) \\ 3x-6y+3x+6y=-9-3 \\ 6x+0y=-12 \\ x=\frac{-12}{6} \\ x=-2 \end{gathered}

We can now use the second equation to find the value of y:

\begin{gathered} x-2y=-3 \\ x+3=2y \\ y=\frac{x+3}{2} \\ y=\frac{-2+3}{2} \\ y=\frac{1}{2} \end{gathered}

The values are x = -2 and y = 1/2.

iv) When we want to multiply two matrices, the required condition is that the number of columns of the matrix on the left is equal the number of rows of the matrix on the right.

In the case of A(2x2) and B(2x1), when we do A*B this condition is satisfied.

But when we try to multiply BA, the number of columns of B is not equal to the number of rows of A, so the matrix mulitplication is not possible.

Answer:

i) det(A) = -12

ii) A is not singular because singular matrices have determinant equal to zero.

iii) x = -2 and y = 1/2.

iv) Is not possible because the number of columns of the first matrix has to be equal to the number of rows of the second matrix.

6 0
1 year ago
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miv72 [106K]

The solutions for -5 +2x^{2} = -6x is option 3. x= \frac{-6 \pm \sqrt{36-4 (2)(-5)}}{4} .

Step-by-step explanation:

Step 1:

First, we must bring the equation to the form of ax^{2} +bx +c =0.

So -5 +2x^{2} = -6x becomes 2x^{2} +6x-5=0.

The value of a is the coefficient of the x^{2} term, the value of b is the coefficient of x term and c is the coefficient of the constant term.

Comparing the above equation to ax^{2} +bx +c =0, we get a = 2, b = 6, and c=-5.

We have the formula x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}.

Step 2:

By substituting the known values, we get

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a} =\frac{-6 \pm \sqrt{6^{2}-4 (2)(-5)}}{2 (2)}.

\frac{-6 \pm \sqrt{6^{2}-4 (2)(-5)}}{2 (2)} = \frac{-6 \pm \sqrt{36-4 (2)(-5)}}{4} .

This is the third option.

8 0
4 years ago
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iren2701 [21]

Answer:

Law of cosines to find missing measures

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Used because it is a SAS triangle

Step-by-step explanation:

This is known as a side, angle, side, or SAS triangle. We can find the missing measures by using the Law of cosines

c^2= a^2+b^2-2ab*cos(C)

7 0
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