Answer:
At any given moment, the red ant's coordinates may be written as (a, a) where a > 0. The red ant's distance from the anthill is 
. The black ant's coordinates may be written as (-a, -a) and the black ant's distance from the anthill is . This shows that at any given moment, both ants are units from the anthill.
Step-by-step explanation:
Given:
red ant's coordinates written as (a,a)
black ant's coordinates are written as (-a, -a)
To find:
The distance of red and black ants from anthill
Solution:
Compute the distance of red ant from the anthill using distance formula
d (red ant) = 
= 
= 
=
So distance of red ant from anthill is
Compute the distance of black ant from the anthill using distance formula
d (black ant) = 
= 
=
=
=
So distance of black ant from anthill is
Hence both ants are
units from the anthill.
The correct answer is B)
.
The denominator of the exponent is the root we are taking. The numerator is the exponent of the radicand. This means 3 will be the denominator, since it is a cubed root, and 2 will be the numerator of m while 5 will be the numerator of n.
Answer:
x = 6
y = -6
Step-by-step explanation:
x + y = 0 (Multiply by -1)
x + 9y= -48
-x - y = 0
x + 9y= -48
8y = -48
y = -6
x + y = 0
x - 6 = 0
x = 6
1 5/9 × 2 6/7=??
To find this out, we have to make both fractions improper fractions, by multiplying the whole numbers with the bottom numbers(denominator) and then adding the numerator(top number).
1 5/9= (9×1) + 5 = 14/9
2 6/7= (7×2) + 6 = 20/7
Now, we multiply them together.
14/9 × 20/7
Cross multiply.
Your answer is now 40/9
Make that into a mixed number.
D) 4 4/9
~Hope I helped!~
