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svetlana [45]
3 years ago
5

Given the reaction: C6H12O6 + 6O2 → 6CO2 + 6H2

Chemistry
2 answers:
ArbitrLikvidat [17]3 years ago
6 0

Answer:

=4moleculesC_6H_{12}O_6

Explanation:

Hello,

In this case, since 24 molecules of carbon dioxide, and considering the given reaction, the following stoichiometric calculation turns out helpful to determine the requested molecules of C₆H₁₂O₆ that are needed:

=24moleculesCO_2*\frac{1molCO_2}{6.022x10^{23}moleculesCO_2}*\frac{1molC_6H_{12}O_6}{6molCO_2}*\frac{6.022x10^{23}moleculesC_6H_{12}O_6}{1molC_6H_{12}O_6}  \\=4moleculesC_6H_{12}O_6

It is clear that Avogadro's number is needed to perform the one to six relationship between C₆H₁₂O₆ and CO₂.

Best regards.

iogann1982 [59]3 years ago
3 0
Use the coefficients as a ratio. 1:6 = x:24. You can write these as fractions and cross multiply, 6x=24. Solve and x=4, so four molecules would be needed
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Answer:

a. Rate = k×[A]

b. k = 0.213s⁻¹

Explanation:

a. When you are studying the kinetics of a reaction such as:

A + B → Products.

General rate law must be like:

Rate = k×[A]ᵃ[B]ᵇ

You must make experiments change initial concentrations of A and B trying to find k, a and b parameters.

If you see experiments 1 and 3, concentration of A is doubled and the Rate of the reaction is doubled to. That means a = 1

Rate = k×[A]¹[B]ᵇ

In experiment 1 and to the concentration of B change from 1.50M to 2.50M but rate maintains the same. That is only possible if b = 0. (The kinetics of the reaction is indepent to [B]

Rate = k×[A][B]⁰

<h3>Rate = k×[A]</h3>

b. Replacing with values of experiment 1 (You can do the same with experiment 3 obtaining the same) k is:

Rate = k×[A]

0.320M/s = k×[1.50M]

<h3>k = 0.213s⁻¹</h3>

6 0
3 years ago
Should someone who lives on the sixth floor of an apartment building be concerned about radon in his or her apartment? Why or wh
torisob [31]

Answer:

The person should not be concerned about radon.

Explanation:

<em>A person living on the sixth floor of an aparment probably should not be concerned about radon</em>. In the conditions of the Earth's atmosphere (temperature and pressure), radon exists as a gas. This gas has a density that is approximately 8 times higher than the density of air (9.73 g/L compared to 1.22 g/L). <em>This means that radon gas would not rise, and instead remain close to the ground</em>, meaning that an apartment on a sixth floor is too far away from the ground for radon gas to reach there.

A gas being denser than air is also the reason why if you blow into a balloon, it will fall to the ground, because CO₂ is denser than air.

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3 years ago
How many electrons are shared in a double covalent bond?
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8 0
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Why do non-metal aroms form covalent bonds e.g. H2O​
Oksana_A [137]

Answer:

Covalent bonds usually occur between nonmetals. For example, in water (H2O) each hydrogen (H) and oxygen (O) share a pair of electrons to make a molecule of two hydrogen atoms single bonded to a single oxygen atom. ... Covalent compounds tend to be soft, and have relatively low melting and boiling points.

7 0
3 years ago
A gas effuses 4.0 times faster than oxygen (o2). what is the molecular mass of the gas? 1.0 g/mol 1.0 g/mol 2.0 g/mol 2.0 g/mol
Anastaziya [24]

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32(molecular mass has no unit )

Explanation:

(16)(o2)

16×2

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5 0
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