Answer: True
Explanation: Ceramics have the property that when the band gap present between the atoms are larger than the light energy then the tend to become opaque because the light scattering is caused . They also show the property of being translucent when there are chances of the light to get a path through the surface of ceramic so they get the light at some parts e.g.porcelain .Therefore the statement given is true that ceramics can be optically opaque or semi-transparent(translucent).
Answer:
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Explanation:
Answer:
>>pounds=13.2
>>kilos=pounds/2.2
Explanation:
Using Matlab to write the program, consider at any time when the weight in pounds is 13.2 lb, this variable of weight is created in MATLAB by typing >>pounds=13.2. To convert it from lb to Kg, we simply divide it by 2.2 hence the second command to created is kilos. For this, the output of the program will be 6 Kg.
Answer:
In ferrous metal iron present but on the other hand in the non ferrous material iron does not present.That is why there is a different heat treatment process for ferrous and nonferrous materials.
Ferrous materials contains iron is the main constitute.Like steel ,cast iron ,wrought iron .Steel and cast iron are the alloy element of iron ans carbon.Wrought iron is the purest from of iron.
Heat treatment process for ferrous materials :
1.Normalizing
2.Annealing
3.Quenching
4.Surface hardening
Heat treatment process for non ferrous materials :
Mostly annealing process is used for non ferrous materials.After annealing non ferrous will become soft.
When two metal plates are joined then they form a bimetallic structure.The bimetallic structure is used to find the relationship of thermal temperature and the mechanical displacement.
The use of bimetallic structure -In clock ,thermometers ,engines.
Answer:
y = -1/24 x³ + 5/12 x² − 35/24 x + 25/12
Explanation:
A cubic has the form:
y = ax³ + bx² + cx + d
Given four points, we can write a system of equations:
1 = a + b + c + d
1/2 = 8a + 4b + 2c + d
1/3 = 27a + 9b + 3c + d
1/4 = 64a + 16b + 4c + d
Solving this algebraically would be time-consuming, but we can use matrices to make it easy.
![\left[\begin{array}{cccc}1&1&1&1\\8&4&2&1\\27&9&3&1\\64&16&4&1\end{array}\right]\left[\begin{array}{cccc}a\\b\\c\\d\end{array}\right]=\left[\begin{array}{cccc}1\\1/2\\1/3\\1/4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%261%261%261%5C%5C8%264%262%261%5C%5C27%269%263%261%5C%5C64%2616%264%261%5Cend%7Barray%7D%5Cright%5D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7Da%5C%5Cb%5C%5Cc%5C%5Cd%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%5C%5C1%2F2%5C%5C1%2F3%5C%5C1%2F4%5Cend%7Barray%7D%5Cright%5D)
First, we find the inverse of the coefficient matrix. This is messy to do by hand, so let's use a calculator:
![\left[\begin{array}{cccc}1&1&1&1\\8&4&2&1\\27&9&3&1\\64&16&4&1\end{array}\right] ^{-1} =-\frac{1}{12}\left[\begin{array}{cccc}2&-6&6&-2\\-18&48&-42&12\\52&-114&84&-22\\-48&72&-48&12\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%261%261%261%5C%5C8%264%262%261%5C%5C27%269%263%261%5C%5C64%2616%264%261%5Cend%7Barray%7D%5Cright%5D%20%5E%7B-1%7D%20%3D-%5Cfrac%7B1%7D%7B12%7D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D2%26-6%266%26-2%5C%5C-18%2648%26-42%2612%5C%5C52%26-114%2684%26-22%5C%5C-48%2672%26-48%2612%5Cend%7Barray%7D%5Cright%5D)
Now we multiply by the solution matrix (again using a calculator):
![-\frac{1}{12} \left[\begin{array}{cccc}2&-6&6&-2\\-18&48&-42&12\\52&-114&84&-22\\-48&72&-48&12\end{array}\right]\left[\begin{array}{cccc}1\\1/2\\1/3\\1/4\end{array}\right] =\left[\begin{array}{cccc}-1/24\\5/12\\-35/24\\25/12\end{array}\right]](https://tex.z-dn.net/?f=-%5Cfrac%7B1%7D%7B12%7D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D2%26-6%266%26-2%5C%5C-18%2648%26-42%2612%5C%5C52%26-114%2684%26-22%5C%5C-48%2672%26-48%2612%5Cend%7Barray%7D%5Cright%5D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%5C%5C1%2F2%5C%5C1%2F3%5C%5C1%2F4%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D-1%2F24%5C%5C5%2F12%5C%5C-35%2F24%5C%5C25%2F12%5Cend%7Barray%7D%5Cright%5D)
So the cubic is:
y = -1/24 x³ + 5/12 x² − 35/24 x + 25/12
