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Pachacha [2.7K]

4 years ago

6

What different tests did the team perform to come up with a workable design?

1 answer:

I am Lyosha [343]4 years ago

5 0

They ran different shapes and materials through a wind tunnel to see which shape and material would decrease energy output so that it takes in equal COthan it puts out.

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For better thermal control it is common to make catalytic reactors that have many tubes packed with catalysts inside a larger sh

Paul [167]

Answer:

the pressure drop is 0.21159 atm

Explanation:

Given that:

length of the reactor L = 2.5 m

inside diameter of the reactor d= 0.025 m

diameter of alumina sphere $dp$ = 0.003 m

particle density = 1300 kg/m³

the bed void fraction $\in =$ 0.38

superficial mass flux m = 4684 kg/m²hr

The Feed is methane with pressure P = 5 bar and temperature T = 400 K

Density of the methane gas $\rho$ = 0.15 mol/dm ⁻³

viscosity of methane gas $\mu$ = 1.429 x 10⁻⁵ Pas

The objective is to determine the pressure drop.

Let first convert the Density of the methane gas from 0.15 mol/dm ⁻³ to kg/m³

SO; we have :

Density = 0.15 mol/dm ⁻³

Molar mass of methane gas (CH₄) = (12 + (1×4) ) = 16 mol

Density = $0.1 5 *\dfrac{16}{0.1^3}$

Density = 2400

Density $\rho_f$ = 2.4 kg/m³

Density = mass /volume

Thus;

Volume = mass/density

Volume of the methane gas = 4684 kg/m²hr / 2.4 kg/m³

Volume of the methane gas = 1951.666 m/hr

To m/sec; we have :

Volume of the methane gas = 1951.666 * 1/3600 m/sec = 0.542130 m/sec

$Re = \dfrac{dV \rho}{\mu}$

$Re = \dfrac{0.025*0.5421430*2.4}{1.429*10^5}$

$Re=2276.317705$

For Re > 1000

$\dfrac{\Delta P}{L}=\dfrac{1.75 \rho_f(1- \in)v_o}{\phi_sdp \in^3}$

$\dfrac{\Delta P}{2.5}=\dfrac{(1.75 *2.4)(1- 0.38)*0.542130}{1*0.003 (0.38)^3}$

$\Delta P=8575.755212*2.5$

$\Delta = 21439.38803 \ Pa$

To atm ; we have

$\Delta P = \dfrac{21439.38803 }{101325}$

$\Delta P =0.2115903087 \ atm$

ΔP ≅ 0.21159 atm

Thus; the pressure drop is 0.21159 atm

4 0

3 years ago

Please read and an<br><br> 3. Many Jacks use hydraullc power.<br> A) O True<br> B) O False

drek231 [11]

Answer:

A) True. I hope this helps

5 0

3 years ago

What is a dynamic load? *

alexira [117]

Answer: Bricks in Building

8 0

3 years ago

Assume that each atom is a hard sphere with the surface of each atom in contact with the surface of its nearest neighbor. Determ

deff fn [24]

Answer:

The classification of the concern is listed in the interpretation segment below.

Explanation:

(a)...

<u>Simple cubic lattice</u>

<u /> $a=2r$

Now,

The unit cell volume will be:

$=a^3$

$=(2r)^3$

$=8r^3$

At one atom per cell, atom volume will be:

$=(1)\times (\frac{4 \pi r^3}{3})$

Then the ratio will be:

$Ratio=\frac{\frac{4 \pi r^3}{3}}{8r^3}\times 100 \ percent$

$=52.4 \ percent$

(b)...

<u>Diamond lattice</u>

The body diagonal will be:

$d=8r=a\sqrt{3}$

$a=\frac{8}{\sqrt{3}}r$

The unit cell volume will be:

$=a^1$

$=(\frac{8r}{\sqrt{3}})^1$

At eight atom per cell, the atom volume will be:

$=8(\frac{4 \pi r^1}{3})$

Then the Ratio will be:

$Ratio=\frac{8(\frac{4 \pi r^1}{3})}{(\frac{8r}{\sqrt{3}})^1}\times 100 \ percent$

$=34 \ percent$

Note: percent = %

5 0

3 years ago

Tom scott thinks a deal with ______ is key to take vamderbilt's place

yan [13]

Answer:

A.

Explanation:

4 0

3 years ago