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fenix001 [56]
2 years ago
10

A steel bar with a diameter of .875 inches and a length of 15.0 ft is axially loaded with a force of 21.6 kip. The modulus of el

asticity of the steel is 29 *106 psi. Determine
Engineering
1 answer:
svetoff [14.1K]2 years ago
3 0

Answer:

35.92 kpsi

Explanation:

Given data:

diameter of the steel bar d = 0.875 in

Area A = πd^2/4 = π(0.875)^2/4

length L = 15.0 ft

Load P = 21.6 kip

Modulus of elesticity E = 29×10^6 Psi

Assume we are asked to determine axial stress in the bar which is given as

\sigma  = Load, P/ Area, A

\sigma  = 4P/\pi d^2

substitute the value

\sigma = \frac{4\times 21.6}{\pi \times (0.875)^2} \\=35.92\ kpsi

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We need to define the variables,

So,

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Therefore, the probability that the repair time is more than 4 horus can be calculate as,

P(x>4)=1-P(x4)= 1-F_x(4)\\P(x>4) = 1-e^{-0.5*4}\\P(x>4) = 1-0.98\\P(x>4) = 0.018

The probability that the repair time is more than 4 hours is 0.136

b) The probability that repair time is at least 12 hours given that the repair time is more than 7 hoirs is calculated as,

P(x\geq 12|x>7)=P(X\geq7+5|x>7)\\P(x\geq12|x>7)=P(X\geq5)\\P(x\geq12|x>7)=1-P(x\leq 5)\\P(x\geq12|x>7)=1-e^{-0.5(2)}

P(x\geq 12|x>7)=0.6321

The probability that repair time is at least 12 hours given that the repair time is more than 7 hours is 0.63

3 0
3 years ago
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IRINA_888 [86]
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3 years ago
Bulk wind shear is calculated by finding the vector difference between the winds at two different heights. Using the supercell w
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See explaination

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15 kts south easterly and 40 kts westerly

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please see attachment

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Explanation:

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Radioactive wastes are temporarily stored in a spherical container, the center of which is buried a distance of 10 m below the e
a_sh-v [17]

Answer:

Outside temperature =88.03°C

Explanation:

Conductivity of air-soil from standard table

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To find temperature we need to balance energy

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3 years ago
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