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nlexa [21]
3 years ago
10

On a trolley ride around an amusement park, a child travelled from one signpost to a second signpost at a constant speed of 125

meters per minute. Was the distance that the child travelled from the first signpost to the second signpost greater than 0.8km? (1km = 1,000meters)
1) It took less than 450 seconds for the child to travel from the first signpost to the second signpost

2) It took more than 400 seconds for the child to travel from the first signpost to the second signpost
Physics
1 answer:
Tomtit [17]3 years ago
5 0

Answer:

Explanation:

Speed given = 125 m /min

125 /60 m /s

In 450 second it will travel

= 450 x 125 / 60

=937.5 m.  

As the distance  is covered in less than 450 seconds , The distance must be less than 937.5 m

In 400 seconds , it will travel

= 400 x 125 / 60

833.33 m

Since the distance is covered in more than 400 seconds , the distance must be more than ie 833.33 .

Hence the distance covered is more than .833 m but less than 937.5

In either case these distance are more than .8 km .

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Bas_tet [7]

Answer:

(a) The value of the ratio m₁/m₂ is 0.581

(b)  the acceleration of the combined masses is 1.139 m/s²

Explanation:

Given;

The acceleration of force applied to M₁, a₁ = 3.10 m/s²

The same force applied to M₂ has acceleration, a₂ = 1.80 m/s²

Let this force = F

According Newton's second law of motion;

F = ma

(a) the value of the ratio m₁/m₂

since the applied force is same in both cases,  M₁a₁ = M₂a₂

\frac{m_1}{m_2} = \frac{a_2}{a_1} \\\\\frac{m_1}{m_2} = \frac{1.8}{3.1} \\\\\frac{m_1}{m_2} = 0.581

(b) the acceleration of m₁ and m₂ combined as one object under the action force F

F = ma

a = \frac{F}{M} \\\\a =  \frac{F}{m_1 + m_2} \\\\a = \frac{F}{0.581m_2 + m_2}\\\\a = \frac{F}{1.581m_2}

But, m_2 = \frac{F}{a_2} \\\\a = \frac{F}{1.581m_2} =  \frac{F*a_2}{1.581F} \\\\a = \frac{a_2}{1.581} \\\\a = \frac{1.8}{1.581} = 1.139 \ m/s^2

Therefore, the acceleration of the combined masses is 1.139 m/s²

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3 years ago
A proton at location A makes an electricfield E-->1 atlocation B. A different proton, placed atlocation B, experiences a forc
luda_lava [24]

Answer:

Explanation:

 |F-->1| =  E-->1 x charge on proton

= 300 x 1.6 x 10⁻¹⁹

Magnitude of electric force on proton

|F-->1| = 480 x 10⁻¹⁹ N .

Inside lithium nucleus , there are three protons so charge on it

= 3 x 1.6 x 10⁻¹⁹ = 4.8 x 10⁻¹⁹ C .

Magnitude of electric force on lithium nucleus

|F-->Li|  =   E-->1 x charge on lithium nucleus

= 300 x  4.8 x 10⁻¹⁹

= 1440 x 10⁻¹⁹ N .

Electron has same charge as that possessed by proton so charge on electron = 1.6 x 10⁻¹⁹ C

Magnitude of force on electron

|F-->1| =  E-->1 x charge on electron

= 300 x 1.6 x 10⁻¹⁹

=  480 x 10⁻¹⁹ N .

7 0
3 years ago
A 30kg bucket of water is lifted vertically 3.0m. How much work was done on the bucket during this movement
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3 years ago
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Atoms form chemical bonds to satisfy the blank rule and become blank​
Masja [62]

Answer:

Atoms form chemical bonds to satisfy the Octet rule and become Stable element.

Explanation:

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Answer:

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Here frequency, f = 2 revolutions per minute

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Angular velocity, ω = 2πf = 0.209 radians/second.

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Linear velocity =  9.6 x 10³ x 0.209 = 2006.4 m/s= 2 km/s

Revolving velocity = 2 km/s

8 0
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