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3 years ago

15

Which of the following is NOT an example of a correct interaction between the

1 answer:

makkiz [27]3 years ago

3 0

Answer:

WE NEED ANSWER CHOICES

Explanation:

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The metric system is now known as the international system of units.<br> a. T<br> b. F

inn [45]

<span>The metric system is the oldest name for the international system of units. The answer is <u>a. True. </u>SI unit or the international systems of units are based on seven basic units; the meter, kilogram, second, ampere, Kelvin, candela and mole. All of these basic units are divided into multiples by a power of ten. For example in meters, 1 meter is equal to: 1000 millimeter, 100 centimeter, 10 decimeter, 0.1 decameter, 0.01 hectometer, 0.001 kilometer and so on and so forth.</span>

6 0

3 years ago

A small mailbag is released from a helicopter that is descending steadily at 2.00 m/s. After 3.00 s.

Misha Larkins [42]

Answer:

Explanation:

Initial velocity of mailbag u = 2 m/s

acceleration downwards a = g = 9.8 m/s²

time t = 3 s

a ) final velocity v = ?

v = u + at

= 2 + 9.8 x 3

= 31.4 m /s

b )

s = ut + 1/2 g t²

s is relative displacement of mailbag

u = relative initial velocity of mailbag = 0

relative acceleration = g = 9.8 m /s²

time t = 3 s

s = 0 + 1/2 x 9.8 x 3²

= 44.1 m

relative displacement of mailbag = 44.1 m .

4 0

2 years ago

iris [78.8K]

Answer:

t = 1.659s

Explanation:

We can use the kinematics equations to solve this questions:

v = u + at

$v^{2} = u^{2} +2as$

where v = Final Velocity, u = initial velocity, a = acceleration, t = time, s = displacement

a) Given information from the question,

u = $\frac{70km}{h} =\frac{(70*1000)m}{(1*3600)s} = 19.444m/s$ (Convert km/h to m/s first)

a = $2m/s^{2}$

s = 35m

Now we can substitute these values into the 2nd kinematics equation to find v, final velocity.

$v^{2} =(19.444)^{2} +2(2)(35)\\v=\sqrt{(19.444)^{2} +2(2)(35)} \\v= 22.761m/s (5.sf)\\$

b) Now we have the final velocity, we can substitute the values into the first kinematics equation to find t , the time taken.

v = u + at

22.761 = 19.444 + 2t

2t = 22.761 - 19.444

t = $\frac{22.761-19.444}{2}$

t = 1.659s

7 0

2 years ago

15. Missy Diwater, the former platform diver or the Ringling Brother's Circus had a speed of 25m/s when she hit the

timurjin [86]

K.E.= 1/2 x MV^2 = 1/2 x 40(kg) x (25x25) =12500J

5 0

2 years ago

The speed of a certain proton is 350 km/s. If the uncertainty in its momentum is 0.100%, what is the necessary uncertainty in it

Evgesh-ka [11]

Answer:

$\Delta x = 1.807 \times 10^{-10}m$

Explanation:

mass of proton, m = 1.67 x 10^-27 kg

speed of proton, v = 350 km/s = 350,000 m/s

Momentum of proton, p = mass x speed

p = 1.67 x 10^-27 x 350000 = 5.845 x 10^-22 kg m /s

uncertainty in momentum, Δp = 0.1 % of p

Δp = $\frac{0.1\times 5.845 \times 10^{-22}}{100}=5.845 \times 10^{-25}$

According to the principle

$\Delta x\times \Delta p \geq \frac{h}{2\pi }$

where, Δx be the uncertainty in position

$\Delta x\times 5.845 \times 10^{-25}= \frac{6.634 \times 10^{-34}}{2\times 3.14}$

$\Delta x = 1.807 \times 10^{-10}m$

5 0

3 years ago